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shepuryov [24]
3 years ago
13

how do the properties of compounds compare to the properties of the elements from which they are composed

Chemistry
1 answer:
Crank3 years ago
6 0
<span>The elements that form the compound don't compare because it doesn't matter about the elements when they are combined. The elements that formed it together is completely different than the outcome compound. </span>
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A container of gas has a volume of 280 mL at a temperature of 22 Celsius if the pressure remains constant what is the volume 44
d1i1m1o1n [39]

Answer:

300.9mL

Explanation:

Given parameters:

V₁  = 280mL

T₁ = 22°C

T₂  = 44°C

Unknown:

V₂ = ?

Solution:

To solve this problem, we apply Charles's law;

  it is mathematically expressed as;

            \frac{V_{1} }{T_{1} }  = \frac{V_{2} }{T_{2} }

We need to convert the temperature to kelvin;

       T₁ = 22°C = 22 + 273 = 295K

       T₂  = 44°C = 44 + 273  = 317K

Input the parameters and solve;

        \frac{280}{295}   = \frac{V_{2} }{317}

  V₂ x 295 = 280 x 317

  V₂ = 300.9mL

5 0
3 years ago
Can anyone teach me what is criss cross method in chemistry​
Solnce55 [7]

Answer:

In the criss-cross method, the numerical value of the ion charge of the two atoms are crossed over, which becomes the subscript of the other ion. Using this technique, we will write the chemical formula of the given compounds.

Criss cross the absolute values to give Al2O3. To find the formula for magnesium oxide:- The oxidation number of Mg is +2 and oxygen is -2. Criss cross the absolute values to give Mg2O2In this example there is a common factor of 2 so divide by 2 to give MgO.

8 0
2 years ago
I still need a bit of help.
Ostrovityanka [42]
H. The atom would no longer be aluminum
If you added a proton to an atom of aluminum it would become a silicone ion
5 0
3 years ago
A sample of neon gas occupies a volume of 752ml at 25k. What volume will the gas occupy at 80k if the pressure remains constant
Anettt [7]

Answer:

The gas occupy 2406.4 mL at 80 K.

Explanation:

Given data:

Initial volume of gas = 752 mL

Initial temperature = 25 K

Final temperature = 80 K

Final volume = ?

Solution:

The given problem is solved by using charle's law.

V₁/T₁ = V₂/T₂

V₂ =  V₁. T₂ /T₁

V₂ = 752 mL × 80 k / 25 K

V₂ = 60160 mL. k/25 K

V₂ =  2406.4 mL

7 0
3 years ago
Suppose a grill lighter contains 50.0 g of butane. How many grams of butane in the lighter would have to be burned to produce 17
Hitman42 [59]

<span>Answer is: mass of burned butane is 11.6 g.</span>

Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.

m(butane) = 50,0 g.

<span> V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷ Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) : n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) = 0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) = 0,2 mol.<span>
m(C</span>₄H₁₀) = n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) = 0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) = 11,6 g.

5 0
3 years ago
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