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OLEGan [10]
3 years ago
15

Given the empirical formula NO with a molar mass of 59.98 g/mol, what is the molecular formula for this compound

Chemistry
1 answer:
Xelga [282]3 years ago
5 0

Answer:

N₂O₂

Explanation:

The empirical formula NO tells us that the number of Nitrogen atoms will always be equal to the number of Oxygen atoms.

The <em>molar mass of the simplest compound, NO</em>, would be:

  • Molar Mass of NO = Molar Mass of N + Molar Mass of O = 30 g/mol

We <u>divide the molar mass of the problem compound by the molar mass of the simplest compound</u>:

  • 59.98 / 30 ≅ 2

This means we<u> multiply the empirical formula times </u><u>2</u>:

  • The molecular formula is N₂O₂
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What is the relatioship between atomic numbers and ionic radii of the elements in Group 1? what is the relationship between atom
Sever21 [200]
As atomic number increases atomic radii also increase down group 1. ionisation energy down group 1 will also decrease because as atomic radii gets bigger there is less electrostatic force between nuclei and electrons so less energy needed to remove valence electron.
6 0
3 years ago
In sience is copper a element or not a element
sukhopar [10]

Answer:

a element

Explanation:

In science copper is a element. It is one of the transition metals found on the periodic table of elements.

Elements are distinct substances that cannot be split-up into simpler substances. Such substances consist of one kind of atom.

There are over a hundred elements that are known till date.

Each elements combines to form a compound

7 0
3 years ago
A compound has a percent composition of 15.24% sodium (molar mass = 22.99
RUDIKE [14]

The empirical formula of the compound obtained from the question given is NaBrO₃

<h3>Data obtained from the question </h3>
  • Sodium (Na) = 15.24%
  • Bromine (Br) = 52.95%
  • Oxygen (O) = 31.81%
  • Empirical formula =?

<h3>How to determine the empirical formula </h3>

The empirical formula of the compound can be obtained as illustrated below:

Divide by their molar mass

Na = 15.24 / 22.99 = 0.663

Br = 52.95 / 79.90 = 0.663

O = 31.81 / 16 = 1.988

Divide by the smallest

Na = 0.663 / 0.663 = 1

Br = 0.663 / 0.663 = 1

O = 1.988 / 0.663 = 3

Thus, the empirical formula of the compound is NaBrO₃

Learn more about empirical formula:

brainly.com/question/24297883

8 0
2 years ago
A sample of seawater has 0.075 g of sodium chloride per mL of solution. How many moles of sodium chloride are there per liter of
amm1812

Answer:

1.28 mol

Explanation:

mole = mass/molar mass

n = v/v/cm³

mass = 0. 075g

v = 1dm³ =1000cm³

n= m/MV=0.075/58.44(1000)

n =1.28 mol

4 0
4 years ago
Compare and contrast 10kg of melting ice and 1kg of freezing water address temperature heat flow thermal energy what is the simp
iris [78.8K]

Answer:

10 kg of ice will require more energy than the released when 1 kg of water is frozen because the heat of phase transition increases as the mass increases.

Explanation:

Hello!

In this case, since the melting phase transition occurs when the solid goes to liquid and the freezing one when the liquid goes to solid, we can infer that melting is a process which requires energy to separate the molecules and freezing is a process that releases energy to gather the molecules.

Moreover, since the required energy to melt 1 g of ice is 334 J and the released energy when 1 g of water is frozen to ice is the same 334 J, if we want to melt 10 kg of ice, a higher amount of energy well be required in comparison to the released energy when 1 kg of water freezes, which is about 334000 J for the melting of those 10 kg of ice and only 334 J for the freezing of that 1 kg of water.

Best regards!

7 0
3 years ago
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