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2 years ago

15

A woman with a mass of 60 kg climbs a set of stairs that are 3m high How much gravitational potential energy does she gain a res

ult of the climb?
Pls show your solution..
MAR AS BRAINLIEST

1 answer:

Bess [88]2 years ago

4 0

540 j

hope it helpssssssssssss

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Please helpp!! Questions 1-5

Fofino [41]

Answer:

1.

A:Time (minutes)

B: Temp(degrees c)

2. Downward trend (temperature goes down as time goes on )

3.

A: not sure

B: temperature

4.the temperature is going down

5. Closes off any open airways

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3 years ago

If I work out rotational energy to be 102.2J which equals kg.M/s^2, and I hadn't factored time into it, would that be Joules per

Marina CMI [18]

Answer:

0.057 joules is needed to create the total rotational energy each second.

Explanation:

The energy rate is the ratio of total energy to time, which coincides with the definition of power at constant rate:

$\dot W = \frac{\Delta E}{\Delta t}$

$\dot W = \frac{102.2\,J}{\left(30\,min\right)\cdot \left(60\,\frac{s}{min} \right)}$

$\dot W = 0.057\,\frac{J}{s}$

$\dot W = 0.057\,W$

0.057 joules is needed to create the total rotational energy each second.

7 0

3 years ago

The Sun delivers an average power of 1.575 W/m2 to the top of Neptune's atmosphere. Find the magnitudes of max and max for the e

FrozenT [24]

Answer:

$1.1486813808\times 10^{-7}\ T$

34.46 V/m

Explanation:

$\mu_0$ = Vacuum permeability = $4\pi \times 10^{-7}\ H/m$

c = Speed of light = $3\times 10^8\ m/s$

I = Intensity = 1.575 W/m²

The maximum magnetic field intensity is given by

$B_m=\sqrt{\dfrac{2\mu_0I}{c}}\\\Rightarrow B_m=\sqrt{\dfrac{2\times 4\pi \times 10^{-7}\times 1.575}{3\times 10^8}}\\\Rightarrow B_m=1.1486813808\times 10^{-7}\ T$

The magnetic field intensity is $1.1486813808\times 10^{-7}\ T$

The maximum electric field intensity is given by

$E_m=B_m\times c\\\Rightarrow E_m=1.1486813808\times 10^{-7}\times 3\times 10^8\\\Rightarrow E_m=34.46\ V/m$

The electric field intensity is 34.46 V/m

8 0

2 years ago

The 68-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P

bogdanovich [222]

Explanation:

Mass of the crate, m = 68 kg

We need to find the resulting acceleration if :

(a) Force, P = 0

P = m a

⇒ a = 0

(b) P = 181 N

$a=\dfrac{P}{m}$

$a=\dfrac{181\ N}{68\ kg}$

$a=2.67\ m/s^2$

(c) P = 352 N

$a=\dfrac{P}{m}$

$a=\dfrac{352\ N}{68\ kg}$

$a=5.17\ m/s^2$

Hence, this is the required solution.

5 0

3 years ago

A big wheel at a theme park has a diameter of 14m and people on the ride complete one revolution in 24s. calculate the distance

just olya [345]

Explanation:

We'll call the radius r and the diameter d:

We also assume that the riders are at a distance r = d/2 = 7m from the center of the wheel.

The period of the wheel is 24s. The tangent velocity of the wheel (and the riders) will be: (2pi/T)*r = 0.8 m/s (circa).

It means that in 3 minutes (180 seconds) they'll run 0.8 m/s * 180s = 144m.

Hopefully I understood the question. If yes, that's the answer.

7 0

2 years ago