The resistance R of a piece of wire is given by
where
is the resistivity of the material, L is the length of the wire and A is its cross-sectional area.
Using this formula, and labeling with A the aluminum and with T the tungsten wire, we can write the ratio between
(the resistance of the tungsten wire) and
(the resistance of the aluminum wire):
the two wires are identical, so L and A are the same for the two wires and simplify in the ratio, and we get:
By using the resistivity of the aluminum:
and the resistivity of the tungsten:
m we can get the resistance of the tungsten wire:
Energy is the capacity for doing work..
Kinetic energy - Moving car
Potential energy - flowing water up the hill
Answer: find the attached figure for a and b
Explanation:
A) The second figure depict electric field lines and equipotential lines for two equal but opposite charges. The equipotential lines can be drawn by making them perpendicular to the electric field lines. The potential is greatest (most positive) near the positive charge and least (most negative) near the negative charge.
B) The figure attached depicts an isolated point charge Q with its electric field lines in blue and equipotential lines in green. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Work is needed to move a charge from one equipotential line to another. Equipotential lines are perpendicular to electric field lines in every case.
Please find the attached file for the figure
The answer is B the transverse waves move perpendicular to the direction the wave travels.
Answer:
32.9166667 m / s^2
Explanation:
s = 4.25km (1000m / 1km)
= 4250m
u = 20m/s
delta T = 20min (60sec / 1min)
= 1200s
Use formula s = ut + (1/2)at^2
4250m = 20m/s * 1200s + (1/2)a*1200s^2
Rearrange it to find a
a = (s-ut) / (1/2 * t^2)
a = (4250m - 20m/s*1200s) / (1/2 * 1200s^2)
a = -32.9166667 m / s^2
