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Andrej [43]
3 years ago
8

A helicopter flies over the arctic ice pack at a constant altitude, towing an airborne 129-kg laser sensor that measures the thi

ckness of the ice (see the drawing). The helicopter and the sensor both move only in the horizontal direction and have a horizontal acceleration of magnitude 2.84 m/s2 . Ignoring air resistance, find the tension in the cable towing the sensor.

Physics
1 answer:
Mashcka [7]3 years ago
7 0

Answer:

1317.52 Newton

Explanation:

Mass of sensor = m = 129 kg

Acceleration of the sensor = a = 2.84 m/s²

g = Acceleration due to gravity = 9.81 m/s²

F_m = Force on the laser sensor due to motion = 129×2.84 = 366.36 N

F_g = Force due to gravity on the laser = mg = 129×9.81 = 1265.49 N

Tension in the cable

T=\sqrt{F_m^2+F_h^2}\\\Rightarrow T=\sqrt{366.36^2+1265.49^2}\\\Rightarrow T=1317.52\ N

∴ The tension in the cable towing the sensor is 1317.52 Newton

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V=2m/2s

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b,v=s/t

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34. A train, starting from rest, accelerates along the platform at a uniform rate of 0.6 m/s2. A passenger standing on the platf
ira [324]

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4.08 s

Explanation:

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so we will have

distance moved by train is given as

d_1 = \frac{1}{2}(0.6) t^2

also the distance moved by passenger

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A resistor uses 100 w of power when connected to 120 v emf. What is the current through the same resistor when connected to a 22
cricket20 [7]

Answer:

Explanation:

Let the resistance of resistor be R .

Power of resistor  V² / R , where V is potential applied .

V² / R = 100

120² / R = 100

R = 120² / 100

= 144 ohm .

Now potential diff applied = 220 V

current = potential diff / resistance

= 220 / 144

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6 0
3 years ago
Establishing a potential difference The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 10
11111nata11111 [884]

Answer:

1.62\times 10^{-8}\ \text{s}

Explanation:

\epsilon_0 = Vacuum permittivity = 8.854\times 10^{-12}\ \text{F/m}

A = Area = 10\times 2\times 10^{-4}\ \text{m}^2

d = Distance between plates = 1 mm

V_c = Changed voltage = 60 V

V = Initial voltage = 100 V

R = Resistance = 1000\ \Omega

Capacitance is given by

C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.854\times 10^{-12}\times 10\times 2\times 10^{-4}}{1\times 10^{-3}}\\\Rightarrow C=1.7708\times 10^{-11}\ \text{F}

We have the relation

V_c=V(1-e^{-\dfrac{t}{CR}})\\\Rightarrow e^{-\dfrac{t}{CR}}=1-\dfrac{V_c}{V}\\\Rightarrow -\dfrac{t}{CR}=\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-CR\ln (1-\dfrac{V_c}{V})\\\Rightarrow t=-1.7708\times 10^{-11}\times 1000\ln(1-\dfrac{60}{100})\\\Rightarrow t=1.62\times 10^{-8}\ \text{s}

The time taken for the potential difference to reach the required level is 1.62\times 10^{-8}\ \text{s}.

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3 years ago
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