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Gre4nikov [31]
3 years ago
14

During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of

74.0 kg and its horizontal component of velocity is 7.00 m/s just before the 65.0 kg performer catches it. If the performer is initially motionless on nearly frictionless roller skates, what is his speed immediately after catching the cannon ball
Physics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

m v1 = (m + M) v2

v2 = m v1 / (m + M)

v2 = 7 * 74 / (74 + 65)

3.73 m/s

74 kg is too heavy for the cannonball (over 150 lbs)

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When a garden hose with an output diameter of 20 mm is directed straight upward, the stream of water rises to a height of 0.13m
SpyIntel [72]

Answer: h = 0.52m

Explanation:

Using the equation of out flow;

A1 × V1 = A2 ×V2

Where A1 = area of the first nozzle

A2 = area of the second nozzle

V1= velocity of flow out from the first nozzle

V2 = velocity of flow out from 2nd nozzle

But AV= area of nozzle × velocity of water = volume of water per second(m³/s).

Now we can set A×V = Area of nozzle × height of rise.

Henceb A1× h1 = A2 × h2 ( note the time cancel on both sides)

D1 = 20mm= 0.02m; h1 = 0.13m

D2 = 10mm = 0.01m; h2= ?

h2 = π(D1/2)²× h1 /π(D2/2)²

h2 = (0.02/2)² × 0.13/(0.01/2)²

= (0.01)² ×0.13 /(0.005)²

= 1.3 × 10^-5/(5 × 10^-3)²

= 1.3 × 10^-5/25 × 10^-6

= (1.3/25) 10^-5 × 10^6

= 0.052× 10

= 0.52m

7 0
3 years ago
A student bangs a brick at the head of a table. Three students are positioned equal distance from the head with their hands on t
iris [78.8K]

Explanation:

that the people closer too the head of the table will feel more vibrations than the people at the end of the table. since the vibrations will slow down as they travel farther down the table

Hope this helps!!

5 0
3 years ago
What is a dependent or responding variable? Can someone help me?
Svetllana [295]

They are a variable that changes as a result of the changes in the manipulated variable

8 0
3 years ago
The cyclotron frequency is the number of revolutions the particle makes in one second. calculate the cyclotron frequency for thi
Roman55 [17]

Answer:

f=qB/2\pim

Explanation:

The cyclotron frequency is the number of revolutions the particle makes in one second. calculate the cyclotron frequency for this particle

solution

The Lorentz force  F_{lorentz} =F_{centripetal}

is the centripetal force  

and makes the particles path to revolve in a circle:

qvB=mv^2/r

radius=r

m=mas of the particle

B=magnetic flux

q=quantity of charge

v=velocity of the particle

v=qBr/m

where v is the velocity of the particle

recall the velocity v=rω

v=2*Pi*f*r

2\pi *f*r=qBr/m

f=qB/2\pim

the cyclotron frequency is therefore f=qB/2\pim

the period(the time it take to make a complete oscillation) will be the inverse of frequency

T=2\pim/qB

4 0
3 years ago
Could the thermal energy of a bowl of hot water equal that of a cold water? Explain.
eduard
No The Thermal energy of the hot water will be higher compared to that of the cold water because Thermal energy is a function of temperature so the higher the temperature the more the energy. That is why during the operation of thermal power plants the water is heated up to super heated state so that the net work out put is higher.
7 0
3 years ago
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