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Alexxx [7]
2 years ago
6

Which has an effect on acceleration (speeding up, slowing down, or changing direction)?

Physics
1 answer:
7nadin3 [17]2 years ago
7 0

Explanation:

If acceleration points in the same direction as the velocity, the object will be speeding up. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.

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An object of mass m travels along the parabola yequalsx squared with a constant speed of 5 ​units/sec. What is the force on the
Dmitriy789 [7]

Explanation:

The object is moving along the parabola y = x² and is at the point (√2, 2).  Because the object is changing directions, it has a centripetal acceleration towards the center of the circle of curvature.

First, we need to find the radius of curvature.  This is given by the equation:

R = [1 + (y')²]^(³/₂) / |y"|

y' = 2x and y" = 2:

R = [1 + (2x)²]^(³/₂) / |2|

R = (1 + 4x²)^(³/₂) / 2

At x = √2:

R = (1 + 4(√2)²)^(³/₂) / 2

R = (9)^(³/₂) / 2

R = 27 / 2

R = 13.5

So the centripetal force is:

F = m v² / r

F = m (5)² / 13.5

F = 1.85 m

7 0
3 years ago
The _______________ of two objects and their distance from each other determine the gravitational force between them. (Please he
Kryger [21]
" ... product of the masses ... "
8 0
3 years ago
Read 2 more answers
So velocity of a balloon? Use V = 2KE over v. A hot air balloon with a mass of 100 kg moves across the sky with 3200 J of kineti
kicyunya [14]

Answer:

700

Explanation:

just put it in kokkokokokokokoook

7 0
2 years ago
Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 23.5 m above water wit
Elodia [21]

As stated in the statement, we will apply energy conservation to solve this problem.

From this concept we know that the kinetic energy gained is equivalent to the potential energy lost and vice versa. Mathematically said equilibrium can be expressed as

\Delta KE = \Delta PE

\frac{1}{2}mv_f^2-\frac{1}{2} mv_0^2 = mgh_2-mgh_1

Where,

m = mass

v_{f,i} = initial and final velocity

g = Gravity

h = height

As the mass is tHe same and the final height is zero we have that the expression is now:

\frac{1}{2}v_f^2-\frac{1}{2} v_0^2 = gh_2

\frac{1}{2} (v_f^2-v_0^2) = gh_2

(v_f^2-v_0^2) = 2gh_2

v_f = \sqrt{2gh_2+v_0^2}

v_f = \sqrt{2(9.8)(23.5)+13.6^2}

v_f = 25.4m/s

7 0
3 years ago
Describe the difference between distance, position, and displacement
nata0808 [166]

Answer:

Explanation:

<em>Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.</em>

<em>Displacement is the difference in the object's position from one time to another.</em>

<em>Distance is the total amount the object has traveled in a certain period of time.</em>

<em />

<em>I hope this helps!</em>

<em />

5 0
2 years ago
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