NaCl molar mass 58.4 g/mol
moles of NaCl = .35 g * 1 mol/58.4 g = 0.005993 mol
volume of solution = 150 mL = 0.15 L
molarity = mol/vol(in L)
[NaCl] = 0.005933mol/0.15L = 0.03995 M = 0.040 M
Answer:
unless it is acted upon a forcd
Answer: 1.58 x 
Explanation:
1 mole of magnesium chloride has a mass of 95.211 g and contains 6.022⋅formula units of magnesium chloride, you can say that,
25.0 g x (6.022 x form units MgCl2) /95.211 = 1.58 x
Answer:
⇒ 3.312 E-13 mol Ni(OH)2 are soluble in 1 L of solution (NaOH)
Explanation:
S S 2S + 0.0218
∴ pKsp Ni(OH)2 = 15.8 = -Log Ksp
⇒ Ksp = 1.585 E-16 = [ Ni2+ ] * [ OH- ]²
∴ pH = 12.34
⇒ pOH = 14- 12.34 = 1.66 = - Log [ OH- ]
⇒ [ OH- ] = 0.0218 M
⇒ Ksp = 1.585 E-16 = S * ( 2S + 0.0218 )²
if we compare the concentration ( 0.0218 ) with the Ksp ( 1.585 E-16 ), then we can neglect the solubility as adding
⇒ 1.585 E-16 = S * ( 0.0218 )²
⇒ 1.585 E-16 = 4.786 E-4 * S
⇒ S = 3.312 E-13 mol/L
∴ soluble moles Ni(OH)2 = 3.312 E-13 mol/L * 1 L Sln = 3.312 E-13 moles
⇒ % S = ( 3.312 E-13 / 0.0218 ) * 100 = 1.513 E-11 %.....we can accept the previous assumption.
Thank you very much for the points! Helped me a lot!
