<span>A.the elements that make up the compound
Tis the answer.</span>
Answer:
Which of the following is a possible set of quantum numbers for a 3p orbital?
Since you are dealing with a 3p-orbital, your principal and angular momentum quantum numbers will be n=3 and l=1 .
Answer:
7650
Explanation:
formula- multiply the volume value by 1e+6
The differential pressure is
797.9 - 715.7 = 82.2 torr = 138815.25 Pa
The height of the mercury in the open-end arm is calculated using
ΔP = ρgh
The density of mercury is 13560 kg/m3
The height of the mercury is
138815.25 Pa = 13560 kg/m3 (9.81 m/s2) h
h = 1.04 m
