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vitfil [10]
2 years ago
11

5. a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m. Calculate

Physics
1 answer:
omeli [17]2 years ago
8 0

Answer:

<h3>The answer is 2 s</h3>

Explanation:

The time of flight can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance covered

v is the velocity

From the question we have

t =  \frac{100}{50}  =  \frac{10}{5}  \\

We have the final answer as

<h3>2 s</h3>

Hope this helps you

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While seeds are forming, another plant part forms around them. Animals eat this part and carry the seeds to a new spot.
Eddi Din [679]

Answer:

<em>The correct option is D) fruit</em>

Explanation:

Both the gymnosperm and the angiosperms plants produce seed. Seeds are an essential part of reproduction in plants.

After fertilization has occurred, the ripened ovule is the part which turns into a seed. The size of the seeds depends on the type if plant.

After fertilization, the ovary forms the fruit. As the ovule is present in the ovule hence after fertilization, the seed which was made from the ovule gets enclosed in the fruit which was made from the ovary.

6 0
3 years ago
A robin flies a distance of 45963 cm. How far has it flown in kilometers?
alina1380 [7]

Answer:

0.46km

Explanation:

45963cm/100cm=459.63m/1000m=0.45963 or 0.46km

6 0
2 years ago
What is the weight of an object with a mass of 6.0 kg on Earth?
gregori [183]
<h2>since weight is measured in newtons, convert the 6 kg to newtons</h2><h3>the formula to convert is kg x 9.807 = N</h3>
  • 6 x 9.807
  • = 58.842 N

hope that helps :))

3 0
2 years ago
Read 2 more answers
A ball is tossed with enough speed straight up so that it is in the air several seconds. (a) What is the velocity of the ball wh
irina1246 [14]

(a) Zero

When the ball reaches its highest point, the direction of motion of the ball reverses (from upward to downward). This means that the velocity is changing sign: this also means that at that moment, the velocity must be zero.

This can be also understood in terms of conservation of energy: when the ball is tossed up, initially it has kinetic energy

K=\frac{1}{2}mv^2

where m is the ball's mass and v is the initial speed. As it goes up, this kinetic energy is converted into potential energy, and when the ball reaches the highest point, all the kinetic energy has been converted into potential energy:

U=mgh

where g is the gravitational acceleration and h is the height of the ball at highest point. At that point, therefore, the potential energy is maximum, while the kinetic energy is zero, and so the velocity is also zero.

(b) 9.8 m/s upward

We can find the velocity of the ball 1 s before reaching its highest point by using the equation:

a=\frac{v-u}{t}

where

a = g = -9.8 m/s^2 is the acceleration due to gravity, which is negative since it points downward

v = 0 is the final velocity (at the highest point)

u is the initial velocity

t = 1 s is the time interval

Solving for u, we find

u=v-at = 0 -(-9.8 m/s^2)(1 s)= +9.8 m/s

and the positive sign means it points upward.

(c) -9.8 m/s

The change in velocity during the 1-s interval is given by

\Delta v = v -u

where

v = 0 is the final velocity (at the highest point)

u = 9.8 m/s is the initial velocity

Substituting, we find

\Delta v = 0 - (+9.8 m/s)=-9.8 m/s

(d) 9.8 m/s downward

We can find the velocity of the ball 1 s after reaching its highest point by using again the equation:

a=\frac{v-u}{t}

where this time we have

a = g = -9.8 m/s^2 is the acceleration due to gravity, still negative

v  is the final velocity (1 s after reaching the highest point)

u = 0 is the initial velocity (at the highest point)

t = 1 s is the time interval

Solving for v, we find

v = u+at = 0 +(-9.8 m/s^2)(1 s)= -9.8 m/s

and the negative sign means it points downward.

(e) -9.8 m/s

The change in velocity during the 1-s interval is given by

\Delta v = v -u

where here we have

v = -9.8 m/s is the final velocity (1 s after reaching the highest point)

u = 0 is the initial velocity (at the highest point)

Substituting, we find

\Delta v = -9.8 m/s - 0=-9.8 m/s

(f) -19.6 m/s

The change in velocity during the overall 2-s interval is given by

\Delta v = v -u

where in this case we have:

v = -9.8 m/s is the final velocity (1 s after reaching the highest point)

u = +9.8 m/s is the initial velocity (1 s before reaching the highest point)

Substituting, we find

\Delta v = -9.8 m/s - (+9.8 m/s)=-19.6 m/s

(g) -9.8 m/s^2

There is always one force acting on the ball during the motion: the force of gravity, which is given by

F=mg

where

m is the mass of the ball

g = -9.8 m/s^2 is the acceleration due to gravity

According to Newton's second law, the resultant of the forces acting on the body is equal to the product of mass and acceleration (a), so

mg = ma

which means that the acceleration is

a= g = -9.8 m/s^2

and the negative sign means it points downward.

7 0
3 years ago
With what force will a car hit a tree if the car has a mass of 3,415 kg and it is accelerating at
weeeeeb [17]

Answer:

F= 17,075\ N

Explanation:

When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.

The accelerating force can be calculated using Newton's second law:

F=m\cdot a

Where m is the mass of the car and a is the acceleration.

F=3,415\ kg\cdot 5\ m/s^2

\boxed{F= 17,075\ N}

3 0
2 years ago
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