The vertical component of force exerted by the hi.nge on the beam will be,142.10N.
To find the answer, we need to know more about the tension.
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How to find the vertical component of the force exerted by the hi.nge on the beam?</h3>
- Let's draw the free body diagram of the system.
- To find the vertical component of the force exerted by the hi.nge on the beam, we have to balance the total vertical force to zero.
- To find the answer, we have to find the tension,
- Thus, the vertical component of the force exerted by the hi.nge on the beam will be,
Thus, we can conclude that, the vertical component of force exerted by the hi.nge on the beam will be,142.10N.
Learn more about the tension here:
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Answer:
ρ/ρ2 = 3 / R₀ the two densities are different
Explanation:
Density is defined as
ρ = M / V
As the nucleus is spherical
V = 4/3 π r³
Let's replace
ρ = A / (4/3 π R₀³)
ρ = ¾ A / π R₀³
b)
ρ2 = F / area
The area of a sphere is
A = 4π R₀²
ρ2 = F / 4π R₀²
ρ2 = F / 4π R₀²
Atomic number is the number of protons in the nucleon in not very heavy nuclei. This number is equal to the number of neutrons, but changes in heavier nuclei, there are more neutrons than protons.
Let's look for the relationship of the two densities
ρ/ρ2 = ¾ A / π R₀³ / (F / 4π R₀²)
ρ /ρ2 = 3 (A / F) (1 / R₀)
In this case it does not say that the nucleon number is A (F = A), the relationship is
ρ/ρ2 = 3 / R₀
I see that the two densities are different
Answer:
2084 kg*m/s
Explanation:
Impulse is change in momentum
Mathematically;
Impulse, J= F*t=mΔv where
F= ma = 1500 * { 30.56 - 16.67}/2*60
F= 1500 *0.11575
F= 174 N
J=F*t
J= 174*120*0.1
J= 2084 kg*m/s
Answer: The answer is 333.3333 repeating
Explanation:
Divide the mass by the volume.