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lorasvet [3.4K]
3 years ago
5

7. How many 1.00 µF capacitors must be connected in parallel to store a charge of 1.00 C with a potential of 110 V across the ca

pacitors?
Physics
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer:

q = C V    charge on 1 capacitor

q = 1 * 10E-6 * 110 = 1.1 *  10E-4  C per capacitor

N = Q / q = 1 / 1.1 * 10E-4  = 9091 capacitors

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The displacement at any given time of an object is x = 6 sin 98t , where the symbols have their usual meanings. i). Proof that t
Fofino [41]

A simple harmonic motion is defined by the amplitude and angular frequency of the oscillation, which are represented in the given function as 6 units and 98 rad/s respectively.

<h3>General wave equation for simple harmonic motion</h3>

y = A sinωt

where;

  • A is amplitude of the motion
  • ω is angular frequency

<h3>Amplitude of the oscillation</h3>

A = 6 units

<h3>Angular frequency of the wave</h3>

ω = 98 rad/s

A simple harmonic motion is defined by the amplitude and angular frequency of the oscillation. Thus, the wave is executing simple harmonic motion.

Learn more about simple harmonic motion here: brainly.com/question/17315536

#SPJ1

5 0
2 years ago
Why is an absorption spectrum especially useful for astronomers?.
creativ13 [48]

Answer:

It has dark lines in it that allow astronomers to determine what elements are in the star. red-shifted (shifted toward the red end of the light spectrum).

Explanation:

4 0
2 years ago
Un observador se halla a 510m. de una pared. entre el observador y la pared, y a igual distancia de ambos, se realiza un disparo
ch4aika [34]

Answer:

a)    t = 0.75 s,  b)  t = 2.25 s

Explanation:

The speed of sound is constant in a material medium

           v = 340 m / s

we can use the relations of uniform motion to find the time

          v = x / t

          t = x / v

In the exercise, the observer's distance to the wall is indicated d = 510 m, it also indicates that the shot is fired at the midpoint

          x = d / 2

       

a) direct sound the distance from the observer to the screen is

           x = 510/2 = 255 m

           t = 255/340

           t = 0.75 s

b) echo sound.

In this case the sound reaches the wall bounces, the distance is

             x = d / 2 + d

             x = 3/2 d

             x = 3/2 510

             x = 765 m

the time is

              t = x / v

              t = 765/340

              t = 2.25 s

5 0
3 years ago
A ball is dropped from a height of 20 meters. At what helght does the ball have a velocity of 10 meters/second?
Sunny_sXe [5.5K]

Answer:

5.10 meters.

Explanation:

v²=u²+2gh

or, (10)²=(0)²+2×9.8×h

or, 19.6h=100

or, h=5.10 meters

Hope, this helps you.

8 0
3 years ago
1. True or False: Most things in motion are accelerating, few things in real life move at a constant speed.
lord [1]
1. False
2. Positive
I’m just joking I don’t know the answersss
5 0
3 years ago
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