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3 years ago

What is the unit of temperature on a solubility graph

Chemistry

2 answers:

Mademuasel [1]3 years ago

8 0

Answer: Celsius

Explanation:

Andrej [43]3 years ago

6 0

Answer:

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Explanation:

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11. Which of the following elements CANNOT violate the octet rule?

rjkz [21]

Answer:

I think it's Nitrogen is right answer

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3 years ago

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How many grams of NaCl are needed to prepare 50.0 grams of 35.0% of salt solution?

nevsk [136]

Answer:

17.5 g

Explanation:

Given data

Mass of solution to be prepared: 50.0 grams

Concentration of the salt solution: 35.0%

The concentration by mass of NaCl in the solution is 35.0%, that is, there are 35.0 grams of sodium chloride per 100 grams of solution. We will use this ratio to find the mass of sodium chloride required to prepare 50.0 grams of a 35.0% salt solution.

$50.0gSolution \times \frac{35.0gNaCl}{100gSolution} = 17.5gNaCl$

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3 years ago

A cold pack manufacturer has decided to change the chemical in their cold pack from ammonium nitrate to ammonium chloride, a saf

My name is Ann [436]

Answer: Tfinal = 7.1°C

Explanation:

heat released or absorbed = mass × specific heat capacity × change in temperature

q = m × cg × ΔT (eqn 1)

Note: ΔT = (Tfinal - Tinitial)

(q = ? ΔHsoln=25.7kJ/mole = 25700J/mole; mass of solution, m = 100 + 35g = 135g; cg = specific heat capacity of water = 4.18 J°C-1g-1; ΔT = ? masss of solute, NH4NO3 = 35g, molar mass of solute, NH4NO3 = 80g)

molar enthalpy of solution, ΔHsoln <em> = heat absorbed or released ÷ moles of solute, </em><em>n</em>

ΔHsoln = q ÷ n

q = ΔHsoln × n

<em>moles solute</em>, n = mass solute (g) ÷ molar mass solute (g mol-1)

moles of solute, n = 35g/80g/mol = 0.4375 moles

q = 25700J/mol × 0.4375 mol = 11243.75J

From equation 1 above, ΔT = q / (m × cg) = 11243.75J / (135 × 4.18 J°C-1g-1) = 19.9°C

Since the reaction is endothermic, Tinitial > Tfinal, therefore, Tfinal = Tinitial - ΔT = 27 - 19.9 = 7.1°C

4 0

4 years ago

20 dekameters equals how many centimeters

stich3 [128]

20000 centimeters because 1 dekameter is 1000 centimeters

3 0

3 years ago

A steel bottle contains argon gas at STP. What is the final pressure if the temperature is changed to 115°C?

Lorico [155]

Answer:

Final pressure is 1.42atm

Explanation:

Based on Gay-Lussac's law, pressure of a gas is directely proportional to its absolute temperature. The equation of this law is:

P₁T₂ = P₂T₁

<em>Where P is pressure and T is absolute temperature of 1, initial state and 2, final state of the gas.</em>

In the problem, initial conditions are Standard Temperature and Pressure, STP, that are 1 atm and 273.15K.

If the final temperature is 115°C = 388.15K (115°C + 273.15 = 388.15K), using Gay-Lussac's law:

P₁T₂ = P₂T₁

1atmₓ388.15K = P₂ₓ273.15K

1.42atm = P₂

<h3>Final pressure is 1.42atm</h3>

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4 0

3 years ago