All categories

3 years ago

What is the unit of temperature on a solubility graph

Chemistry

2 answers:

Mademuasel [1]3 years ago

8 0

Answer: Celsius

Explanation:

Andrej [43]3 years ago

6 0

Answer:

Khfxgkhxxkfhkugxxiufxhfixiyf

Explanation:

Xlufy8fxtukuxfxtu

You might be interested in

Find the enthalpy of neutralization of HCl and NaOH. 137 cm3 of 2.6 mol dm-3 hydrochloric acid was neutralized by 137 cm3 of 2.6

liraira [26]

Answer : The correct option is, (D) 89.39 KJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=2.6mole/L\times 0.137L=0.3562mole$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.3562 mole of HCl neutralizes by 0.3562 mole of NaOH

Thus, the number of neutralized moles = 0.3562 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $137ml+137ml=274ml$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 274ml=274g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 274 g

$T_{final}$ = final temperature of water = 325.8 K

$T_{initial}$ = initial temperature of metal = 298 K

Now put all the given values in the above formula, we get:

$q=274g\times 4.18J/g^oC\times (325.8-298)K$

$q=31839.896J=31.84KJ$

Thus, the heat released during the neutralization = -31.84 KJ

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -31.84 KJ

n = number of moles used in neutralization = 0.3562 mole

$\Delta H=\frac{-31.84KJ}{0.3562mole}=-89.39KJ/mole$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 89.39 KJ/mole

3 0

3 years ago

Question 5 (1 point)

Marianna [84]

Answer:

P=12.16 atm

Explanation:

Using the formula of ideal gas law:

PV = nRT

P= nRT/V

n= number of moles

R= Avogadro constant = 0.0821

T= Temperature in K => ºC + 273.15 K

P= (1.50 moles)(0.0821)( 296.15 K)/ 3.00L

P= 12.15

7 0

3 years ago

How fast must a 56.5-g tennis ball travel in order to have a de Broglie wavelength that is equal to that of a photon of green li

nikklg [1K]

Answer:vv

$v=2.17\times 10^{-26}\ m/s$

Explanation:

The expression for the deBroglie wavelength is:

$\lambda=\frac {h}{m\times v}$

Where,

$\lambda$ is the deBroglie wavelength

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

m is the mass of = $56.5\ g=0.0565\ kg$

v is the speed.

Wavelength = 5400 Å = $5400\times 10^{-10}\ m$

Applying in the equation as:-

$5400\times 10^{-10}=\frac{6.626\times 10^{-34}}{0.0565\times v}$

$v=\frac{331300000}{10^{34}\times \:1.5255}\ m/s$

$v=2.17\times 10^{-26}\ m/s$

7 0

3 years ago

Materials: • One disposable plastic cup • One disposable plastic spoon (plastic fork or knife may be used instead) • Thermometer

Leya [2.2K]

I'm not sure what the question is, this is a lab proecdure

4 0

3 years ago

For a reaction to occur, energy must be _____ to break chemical bonds.

lapo4ka [179]

Answer: The correct answer is absorbed.

Explanation:

Bond formation is a type of exothermic process. In these reactions when two atoms come close to each other, energy is released in this process.

On the other hand, in the breaking of bond, energy is required because the atoms are to be separated from each other. This is a type of endothermic process. So, the energy must be absorbed.

Hence, the correct answer is absorbed.

6 0

3 years ago

Read 2 more answers