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ivolga24 [154]
3 years ago
9

HELP ASAP - How much energy is lost when 80.0 grams of steam at 100.C turns into liquid water at 100.C?

Chemistry
1 answer:
Mice21 [21]3 years ago
7 0

Answer:

Q = 43,000 calories = 180,000 joules = 180 Kilojoules

Explanation:

Heat flow for phase change can be defined as Q = m·ΔHv  

ΔHv = Heat of Vaporization for water = 540 calories/gram = 2259 joules/gram = 2.259 Kilojoules/gram

m = mass of object of interest ( in this problem 80 grams steam 100°C converting to 80 grams of water at 100°C

Q = m·ΔHv = 80g x 540 cals/g =43.200 calories x 4.184 joules/cal = 180,748.8 joules (calculator answer) => 180,000 joules (2 sig. figs.) = 180 Kj

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Answer:

By the Pauling rule, of EN

Explanation:

EN means electronegativity, the ability of atoms to attract electrons.

In the periodic table each atom, has a value of EN.

When there are two atoms bonded, you must substract the EN (the high - the low) → ΔEN

It depends on the ΔEN, that you can define a bond as ionic, covalent or metallic.

Ionic ΔEN → > 1.7

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Answer:

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In order to <u>convert from moles of Al₂O₃ into moles of Al</u>, we'll need to use<em> the stoichiometric coefficients</em>, using a conversion factor that has Al₂O₃ moles in the denominator and Al moles in the numerator:

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