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sergejj [24]
3 years ago
15

What are the laws and calculations governing gas behavior?

Chemistry
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

Laws governing gas behavior.

Explanation:

Boyle's law:

It relates the pressure and volume of an ideal gas at a constant temperature.

According to this law:

"The volume of a fixed amount of gas at constant temperature is inversely proportional to its pressure".

P  \alpha   V.

Charle's law:

It relates the volume and absolute temperature of an ideal gas at a constant pressure.

According to this law:

"The volume of a fixed amount of gas at constant pressure is directly proportional to its absolute temperature".

V   \alpha   T.

Avogadro's law:

According to this law:

equal volumes of all gases under the same conditions of temperature and pressure contain, an equal number of moles.

V   \alpha    n.

Ideal gas equation:

By combining all the above-stated gas laws, this equation is formed as shown below:

V  \alpha   \frac{nT}{P} \\=> V= R. nT/ P\\=>PV=nRT

R is called universal gas constant.

It has a value of 0.0821L.atm.mol-1.K-1.

SSSSS [86.1K]3 years ago
4 0

Answer:

Boyle's law, Charle's law,  Guy Lussac's law and Avogadro's law

Explanation:

All the gases behaves similarly when the environment conditions are normal. But when the physical condition changes like when the pressure, volume or temperature changes, the gas behaves differently and shows a deviation.

The number of gas laws are :

Boyle's Law

Boyle's law states that when the temperature remaining constant, the pressure of the gas varies inversely to the volume of the gas.

i.e.   P \propto \frac{1}{V}

Charle' law

Charle's law states that when pressure is constant, the temperature of a gas is directly proportional to the volume.

i.e. , $T \propto V$

Gay Lussac's law

Gay - Lussa law states the volume and the mass of the pressure of the gas is directly proportional to the  temperature of the gas.

i.e. P.T = constant

Avogadro's law

It states that under the conditions of same pressure as well as temperatures, the gases having equal volumes will have same numbers of molecules.

i.e. \frac{V_1}{n_1}=\frac{V_2}{n_2} = constant

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<h3>How to determine the change in the temperature of water</h3>
  • Initial temperature of water (T₁) = 25 °C
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Change in temperature (ΔT) = 68 – 25

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<h3>How to determine the heat absorbed by the water</h3>

The absorbed by the water can be obtained as illustrated below:

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<h3>How to determine the energy released by methane in the experiment</h3>
  • Heat absorbed by water = 89956 J
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Heat absorbed by water = 30% of heat released by methane

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89956 = 0.3 × heat released by methane

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Heat released by methane = 89956 / 0.3

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Q = m × ΔH

Divide both sides by m

ΔH = Q / m

ΔH = 299853.33 / 2.5

ΔH =119941.33 J/g

Learn more about heat transfer:

brainly.com/question/6363778

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