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2 years ago

What is the equivalent resistance of the circuit?

Physics

2 answers:

bagirrra123 [75]2 years ago

7 0

Answer:

Explanation:

A P E X

Alona [7]2 years ago

4 0

The correct answer is option B. i.e. 60 ohm.
The diagram is attached.

Since all the resistances are attached in series.
Hence, the total resistance will be the sum of all resistances.

R_total = R_1+R_2+ R_3
= 10+20+30
= 60 ohms.

Therefore, option c is correct answer.

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A car initially traveling 7 m/s speeds up uniformly at a rate of 3 m/s2 until it reaches a velocity of 22 m/s. How much time did

dezoksy [38]

Answer:

t = 5 s

Explanation:

Data:

Initial Velocity (Vo) = 7 m/s
Acceleration (a) = 3 m/s²
Final Velocity (Vf) = 22 m/s
Time (t) = ?

Use formula:

$\boxed{t=\frac{Vf - Vo}{a}}$

Replace:

$\boxed{t=\frac{22\frac{m}{s} -7\frac{m}{s}}{3\frac{m}{s^{2}}}}$

Solve the subtraction of the numerator:

$\boxed{t=\frac{15\frac{m}{s}}{3\frac{m}{s^{2}}}}$

It divides:

$\boxed{t=5\ s}$

How much time did it take the car to reach this final velocity?

It took a time of <u>5 seconds.</u>

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2 years ago

the length of time it takes a planet to revolve around the sun is equivalent to witch of the following?

Marina86 [1]

It really depends on how far or close the planet is from the sun

6 0

2 years ago

Read 2 more answers

How is the mass of a body measured ? Write in brief.<br>

skad [1K]

Answer:

Mass is the quantity of matter contained in a body. The mass of an object is measured in kilogram (kg).

Explanation:

3 0

3 years ago

Read 2 more answers

On earth, two parts of a space probe weigh 14500 N and 4800 N. These parts are separated by a center-to-center distance of 18 m

Nastasia [14]

Answer:

$F = 1.489*10^{-7} N$

Explanation: Weight of space probes on earth is given by: $W= m*g$

W= weight of the object( in N)

m= mass of the object (in kg)

g=acceleration due to gravity(9.81 $\frac{m}{s^{2} }$ )

Therefore,

$m_{1} = \frac{14500}{9.81}$

$m_{1} = 1478.08 kg$

Similarly,

$m_{2} = \frac{4800}{9.81}$

$m_{2} = 489.29 kg$

Now, considering these two parts as uniform spherical objects

Also, according to Superposition principle, gravitational net force experienced by an object is sum of all individual forces on the object.

Force between these two objects is given by:

$F = \frac{Gm_{1} m_{2}}{R^{2} }$

G= gravitational constant ( $6.67 * 10^{-11} m^{3} kg^{-1} s^{-2}$ )

$m_{1} , m_{2}$ = masses of the object

R= distance between their centres (in m)(18 m)

Substituiting all these values into the above formula

$F = 1.489*10^{-7} N$

This is the magnitude of force experienced by each part in the direction towards the other part, i.e the gravitational force is attractive in nature.

7 0

3 years ago

Can you help me with this?

Natasha2012 [34]

Answer:

Explanation:

so basically I am domb so I can not help you

4 0

2 years ago