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2 years ago

1. A hydraulic lift is to be used to lift a truck masses 5000 kg. If the diameter of the

Physics

1 answer:

zheka24 [161]2 years ago

7 0

Answer:

a) F = 4.9 10⁴ N, b) F₁ = 122.5 N

Explanation:

To solve this problem we use that the pressure is transmitted throughout the entire fluid, being the same for the same height

1) pressure is defined by the relation

P = F / A

to lift the weight of the truck the force of the piston must be equal to the weight of the truck

∑F = 0

F-W = 0

F = W = mg

F = 5000 9.8

F = 4.9 10⁴ N

the area of the pisto is

A = pi r²

A = pi d² / 4

A = pi 1 ^ 2/4

A = 0.7854 m²

pressure is

P = 4.9 104 / 0.7854

P = 3.85 104 Pa

2) Let's find a point with the same height on the two pistons, the pressure is the same

$\frac{F_1}{A_1} = \frac{F_2}{A_2}$

where subscript 1 is for the small piston and subscript 2 is for the large piston

F₁ = $\frac{A_1}{A_2} \ F_2$

the force applied must be equal to the weight of the truck

F₁ = $( \frac{d_1}{d_2} )^2\ m g$

F₁ = (0.05 / 1) ² 5000 9.8

F₁ = 122.5 N

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