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Vlada [557]
3 years ago
13

The carrot hangs from the ceiling by two ropes (1 and 2).

Physics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer:

The Answer is D!

Explanation:

I checked it on Khan Academy.

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Imagine you are on the top of a mountain with four basketballs. The mass of the four basketballs are 100 kilograms, 200 kilogram
pentagon [3]

Answer:

400 kilogram

Explanation:

Force exerted is directly proportional to the mass of an object.

F=ma where m is mass and a is acceleration. Taking uniform acceleration on all objects then the larger the mass the higher the force and vice versa. Theredore, among the masses given, 400 kilograms is the largest hence it exerts the largest force at the bottom

5 0
3 years ago
A center-seeking force related to acceleration is _______ force.
Gennadij [26K]
<span>A center-seeking force related to acceleration is centripetal force. The answer is letter A. The rest of the choices do not answer the question above.</span>
4 0
3 years ago
I NEED ANSWER ASAP
umka21 [38]

Answer:

97% will sink below the water

Explanation:

Waters density is 1 g/cm3

If an object's density is greater than 1g/cm3, it will sink. If it's less then it would float. 1-0.97 = 0.03. Only 3% of the ice would show while 97 will be under.

7 0
3 years ago
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Gladiators of Physics Plz Help On This Question. Steps will help! with formula
arsen [322]
Simplified gravitational potential energy:
v = mgh

m mass
g gravitational acceleration, on earth = 9.81m/s²
h height

Solve for height.
8 0
3 years ago
A basketball player standing under the hoop launches the ball straight up with an initial velocity of v₀ = 3.25 m/s from 2.5 m a
matrenka [14]

Answer: 0.53m

Explanation:

According to the equation of motion v²= v₀²+2as

Since the body is launched upward, the final velocity at the maximum height will be "zero" since the body will momentarily be at rest at the maximum height i.e v = 0

Initial velocity given (v₀) = 3.25 m/s

The body is also under the influence of gravity but the acceleration due to gravity will be negative being an upward force (a = -g) and the distance (s) will serve as our maximum height (h)

The equation of motion will.now become

V = v₀² -2gh

Where v = 0 v₀ = 3.25m/s g = 10m/s h = ?

0 = 3.25² - 2(10)h

0 = 10.56 - 20h

-10.56 = -20h

h = 10.56/20

h = 0.53m

Therefore, the maximum height, h (in meters), above the launch point that the basketball will achieve is 0.53m

6 0
3 years ago
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