Answer:
2.08×10^24 atoms
Explanation:
set up a mole to atom ratio:
3.47moles 1 mole
------------------ = ----------------------------
x atoms 6.02×10^23 atoms
cross multiply:
3.47 mole × 6.02 × 10^23 = 2.08×10^24 atoms
Answer:
A buffer solution is prepared by adding 13.74 g of sodium acetate (NaC2H3O2) and 15.36 g of acetic acid to enough water to make 500 mL of solution.
Calculate the pH of this buffer.
Explanation:
The pH of a buffer solution can be calculated by using the Henderson-Hesselbalch equation:
![pH=pKa+log\frac{[salt]}{[acid]}](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D)
The pH of the given buffer solution can be calculated as shown below:
When we talk about the gram weight of any food item, it may or may not include the gram weight of its different nutrient molecules. It may have different reasons to it. One of the reasons can be because the nutrient molecule might contain a large percentage or proportion of water. Also, the nutrient molecules might be insoluble or indigestible fiber so it does not add up to the total gram weight of food.
Answer:
Explanation:
Given parameters:
Number of given calories = 614 cal
Note that 1cal = 4.18J
Now to convert the given calories to joule, we use the relationship below:
Since 1Cal gives 4.18Joule of energy
614Cal will produce 4.18 x 614;
2566.52J of energy.
This written as 2.57 x 10³J because it has three significant numbers of 2, 5 and 7.
In writing an operation that involves deducing the significant numbers, we simply express our answer to that shows the lowest number of significant numbers. Our problem has 3 significant numbers each and the answer is given in that regard.
Answer:
Explanation:
Given the compound 
The steps of reaction:
<u>But this intermediate product has a resonance: </u>
The reaction with I-
