Question

A steel beam is rotated in a horizontal plane to provide the centripetal acceleration for training pilots. If the pilot sits 2.19 m from the center of rotation, at what speed must he rotate in order to experience a horizontal centripetal acceleration of 65.8 m/s/s?

Answer 1

Given :

Pilot sits 2.19 m from the center of rotation.

Horizontal centripetal acceleration is 65.8 m/s².

To Find :

The angular velocity of the pilot .

Solution :

We know, centripetal acceleration is given by :

$a = \omega^2 r\\\\\omega = \sqrt{\dfrac{a }{r}}\\\\\omega = \sqrt{\dfrac{65.8 }{2.19}}\\\\\omega = 5.48\ s^{-1}$

Hence, this is the required solution.