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nexus9112 [7]
3 years ago
12

What is an equation of the line that passes through the points (-3, 1) and (–6, 6)?

Mathematics
1 answer:
Allushta [10]3 years ago
7 0
(y2-y1)/(x2-x1)

(6-1)/(-6- -3)= 5/-3

slope= -5/3

y=-5/3x + b

6=-5/3(-6)+b

b or the y-int= -4

therefore the equation is y=-5/3x -4
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