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LUCKY_DIMON [66]

3 years ago

12

How does the wavelength emitted by an object relate to its temperature?

1 answer:

OlgaM077 [116]3 years ago

8 0

Explanation:

I haven't actually seen the answer I'm looking for but I think the answer is when temperatures are lower the wavelength is longer

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Baseboard heaters are basically electric resistance heaters and are frequently used in space heating. A homeowner claims that he

sveta [45]

Answer:

No

Explanation:

The work that can be turned into heat equals 100% and there is no thermodynamic law that says that cannot be.

7 0

3 years ago

if a cyclist is travelling a road due east at 12km/h and a wind is blowing from south-west at 5km/h. find the velocity of the wi

slamgirl [31]

Answer:

The velocity of wind with respect to cyclist is $-15.5 \widehat{i} - 3.5 \widehat{j}$ .

Explanation:

speed of cyclist = 12 km/h east

speed of wind = 5 km/h south west

Write the speeds in the vector form

$\overrightarrow{vc} = 12 \widehat{i}\\\\overrightarrow{vw} = - 5 (cos 45 \widehat{i} + sin 45 \widehat{j})\\\\\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}$

The velocity of wind with respect to cyclist is

$\overrightarrow{vw} =-3.5 \widehat{i} - 3.5 \widehat{j}\overrightarrow{v_(w/c)} = \overrightarrow{vw}-\overrightarrow{vc}\\\\\overrightarrow{v_(w/c)} = - 3.5 \widehat{i} - 3.5 \widehat{j} - 12 \widehat{i}\\\\\overrightarrow{v_(w/c)} =-15.5 \widehat{i} - 3.5 \widehat{j}$

7 0

3 years ago

A dart is thrown horizontally at a target's center that is 5.00 m, away. The dart hits the target 0.150 m below the targets cent

boyakko [2]

Answer:

v₀ₓ = 28.6 m / s

Explanation:

This is a missile throwing exercise

y = $v_{oy}$ t - ½ g t²

as the dart is thrown horizontally the vertical velocity is zero (I go = 0)

y = - ½ g t²

t = $\sqrt{- \frac{2y}{g} }$

let's calculate

t = $\sqrt{- \frac{2 \ (-0.150)}{9.8} }$

t = 0.175 s

the expression for horizontal displacement is

x = v₀ₓ t

v₀ₓ = x / t

v₀ₓ = 5.00 / 0.175

v₀ₓ = 28.6 m / s

7 0

3 years ago

Find the magnitude of the gravitational force a 63.5 kg person would experience while standing on the surface of Earth with a ma

Anastaziya [24]

Answer: 3976N

Explanation:

Using the formula for calculating gravitational force between two masses, we have

F = GMm/r^2

Where G is the gravitational constant

M and m are the masses

r is the distance between the masses

F= 6.673 × 10-¹¹ × 5.98 × 10²⁴ × 63.5/ (6.37 × 10^6)^2

F= 2.533×10^16/6.37×10^12

F= 0.3976×10⁴N

F= 3976N

3 0

3 years ago

A ladder of length 10 is leaning against a wall. The vertical wall is frictionless while the horizontal surface is rough. The an

bogdanovich [222]

Answer:

105.1N

Explanation:

According to the newton second law

$\sum F_x = ma_x\\F_m - F_f = ma_x\\$

Since the acceleration is zero, then;

$F_m - F_f = 0\\Fm = F_f\\$

Since;

$F_m = mg sin \theta, \ hence \ F_f = mg sin \theta$

Given the following

mass of ladder m = 14kg

acceleration due to gravity g = 9.8m/s²

θ = 50°

Substitute

$F_f = 14(9.8)sin50\\F_f = 14(7.5072)\\F_f = 105.1N\\$

Hence the magnitude of the friction force (in N) exerted on the ladder in the point of contact with the horizontal surface is 105.1N

8 0

3 years ago