Answer:
Volume = 3.86 ml (Approx)
Explanation:
Given:
Density of cadmium = 8.65 g/ml
Mass of pure object = 33.4 g
Find:
Volume pure cadmium
Computation:
Volume = Mass / Density
Volume = 33.4 / 8.65
Volume = 3.86 ml (Approx)
Monosaccharides are the simplest carbohydrates. Although glucose and fructose have the same molecular formula they have different structures or the atoms are arranged differently from each other and this is evident in the way they react, behave and in their properties.
We can rephrase the statement with a little more specificity in order to understand the answer here.
The mass of the products can never be more than the The mass that is expected.
Answer:
The water will absorb 1004.16 Joule of heat
Explanation:
Step 1: Data given
Mass of the metal = 58.00 grams
Temperature of the metal = 100.00 °C
Mass of water = 60.00 grams
Temperature of water = 18.00 °C
Final temperature = 22.00 °C
Specific heat of water = 4.184 J/g°C
Step 2: Calculate the amount of heat absorbed by the water in joules
Q = mass *specific heat *ΔT
⇒ with Q = the heat absorbed by water
⇒ with mass of water = 60.00 grams
⇒ with specific heat of water = 4.184 J/g°C
⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C
Q = 60.00 * 4.184 J/g°C * 4.0 °C
Q = 1004.16 J
The water will absorb 1004.16 Joule of heat
Answer:-
Carbon
[He] 2s2 2p2
1s2 2s2 2p2.
potassium
[Ar] 4s1.
1s2 2s2 2p6 3s2 3p6 4s1
Explanation:-
For writing the short form of the electronic configuration we look for the nearest noble gas with atomic number less than the element in question. We subtract the atomic number of that noble gas from the atomic number of the element in question.
The extra electrons we then assign normally starting with using the row after the noble gas ends. We write the name of that noble gas in [brackets] and then write the electronic configuration.
For carbon with Z = 6 the nearest noble gas is Helium. It has the atomic number 2. Subtracting 6 – 2 we get 4 electrons. Helium lies in 1st row. Starting with 2, we get 2s2 2p2.
So the short term electronic configuration is [He] 2s2 2p2
Similarly, for potassium with Z = 19 the nearest noble gas is Argon. It has the atomic number 18. Subtracting 19-18 we get 1 electron. Argon lies in 3rd row. Starting with 4, we get 4s1.
So the short electronic configuration is
[Ar] 4s1.
For long term electronic configuration we must write the electronic configuration of the noble gas as well.
So for Carbon it is 1s2 2s2 2p2.
For potassium it is 1s2 2s2 2p6 3s2 3p6 4s1
