Answer:
13.5 moles of AgNO₃
Explanation:
To determine the reaction:
Reactants: AgNO₃ and Cu
Products: Cu(NO₃)₂ and Ag
2 moles of AgNO₃ react to 1 mol of Cu, in order to produce 1 mol of Cu(NO₃)₂ and 2 moles of solid silver.
2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag
Our production was 6.75 moles of Cu(NO₃)₂
Let's make the rule of three:
1 mol of Cu(NO₃)₂ is produced by 2 moles of AgNO₃
Then, our 6.75 moles were definetely produced by (6.75 . 2) /1 = 13.5 moles.
If the copper was in excess, then the silver nitrate is the limiting reactant:
2 mol of AgNO₃ can produce 1 mol of Cu(NO₃)₂
Then, 13.75 moles of silver nitrate must produce (13.5 . 1) /2 = 6.75 moles of Cu(NO₃)₂
