Hello!
This question can be solved using the
Henderson-Hasselbach equation, but first we need to know the value of pKa
pKa= -log(Ka)= -log(7,1*10⁻⁶)=5,15
Now, we apply the equation:
So, the pH of this solution would be
4,98
Have a nice day!
50.00ml*(10^-3L/ml)*(3.91moles/L) = 0.196 mol
C it illustrates possible outcomes
B all of these will increase the strength of the magnet