Question

0.450 gram of Fe contains how many atoms?

Answer 1

Answer:

0.450 grams of Fe contains 4.85*10²¹ atoms

Explanation:

Molar mass is the mass of one mole of a substance, which can be an element or a compound.

In this case, the molar mass of iron Fe is 55.85 g / mole. Then you can apply the following rule of three: if by definition of molar mass 1 mole of Fe contains 55.85 grams, then how many moles will contain 0.450 grams?

$amount of moles of Fe=\frac{0.450 grams*1 mole}{55.85 grams}$

amount of moles of Fe=8.06*10⁻³ moles

On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if by definition of Avogadro's Number 1 mole of Fe contains 6.023*10²³ atoms, 8.06*10⁻³ moles how many atoms does it contain?

$amount of atoms=\frac{8.06*10^{-3}moles*6.023*10^{23}atoms }{1 mole}$

amount of atoms=  4.85*10²¹ atoms

0.450 grams of Fe contains 4.85*10²¹ atoms