Answer:
Explanation:
We shall write the velocities given in vector form to make the solution easy.
The velocity of water with respect to earth that is waV(e) makes 30 degree with north or 60 degree with east so in vector form
waV(e) = 2.2 cos 60 i + 2.2 sin 60 j
waV(e) = 1.1 i + 1.9 j
Similarly , velocity of wind with respect to earth that is wiV(e) , is making 50 degree with west or - ve of x axes so we cal write it in vector form as follows
wiV(e) = - 4.5 cos 50 i - 4.5 sin 50 j
wiV(e) = - 2.89 i - 3.45 j
Now we have to calculate velocity of wind with respect to water that is
wiVwa
wiV( wa) = wiV ( e)+ eV(wa)
= wiV( e)- waV(e)
- 2.89 i - 3.45 j - 1.1 i - 1.9 j
= - 3.99 i - 5.35 j
Magnitude of this relative velocity
D² = 3.99² + 5.35²
d = 6.67 m /s
Answer:
Final speed = 2.067 m/s
Explanation:
We are told that the child weighs 26 kg.
Also, that the wagon weighs 5kg.
Thus,initial mass of the child and wagon with ball is;
m_i = 26 + 5 = 31 kg.
Also, we are told that the child now dropped 1.5 kg ball from the wagon. So,
Final mass is;
m_f = 26 + 5 - 1 = 30 kg
Now, from conservation of linear momentum, we know that;
Initial momentum = final momentum
Thus;
m_i * v_i = m_f * v_f
Where v_i is initial velocity and v_f is final velocity.
Making v_f the subject, we have;
v_f = (m_i * v_i)/m_f
We are given that initial velocity v_i = 2 m/s
Plugging in the relevant values, we have;
v_f = (31 * 2)/30
v_f = 2.067 m/s
Answer:
Explanation:
<u><em>Finding the net force:</em></u>
<u><em>Firstly , we'll find force of Friction:</em></u>
Where 
is the coefficient of friction and m = 13.6 kg
<u><em>Now, Finding the net force:</em></u>
<u><em>Finding Acceleration:</em></u>
Answer:
Power is the rate at which work is done. It is the work/time ratio. Mathematically, it is computed using the following equation. The standard metric unit of power is the Watt.
Explanation:
