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DanielleElmas [232]
3 years ago
11

A feather is dropped on the moon from a height of 1.40 meters. The acceleration due to gravity on the moon is 1.67 m/s2. Determi

ne the time for the feather to fall on the surface of the moon.
Physics
1 answer:
RoseWind [281]3 years ago
7 0

Distance = (1/2) (acceleration) (time)²

1.4m = (0.835 m/s²) (time)²

(time)² = (1.4/0.835) s²

<em>time = 1.295 s</em>

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The planet Krypton has a mass of 7.6 × 1023 kg and radius of 1.7 × 106 m. What is the acceleration of an object in free fall nea
olga55 [171]

Answer:

17.55 m/s²

Explanation:

Parameters given:

Mass of Krypton, M = 7.6 * 10^23 kg

Radius, R = 1.7 * 10^6 m

Gravitational constant, G = 6.6726 * 10^(-11) Nm²/kg²

Acceleration due to gravity of planet of mass M is given as:

g = GM/R²

Since the object is close to the surface of Krypton, we can say that the distance from the Centre of Krypton is the radius of the planet Krypton.

Therefore,

g = (6.6726 * 10^(-11) * 7.6 * 10^23)/(1.7 * 10^6)²

g = 17.55 m/s²

5 0
4 years ago
3. The propeller of a World War II fighter plane is 2.30 m in diameter. (a) What is its angular velocity in radians per second i
Darya [45]

Answer:

(a) Angular velocity will be 125.6 rad/sec

(b) Linear velocity will be 144.44 m /sec

(c) Centripetal acceleration = 1849.3031 g

Explanation:

We have given diameter d = 2.30 m

So radius r = \frac{d}{2}=\frac{2.30}{2}=1.15m

(a) Speed is given as 1200 rev/min

We know that angular velocity is given by \omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 1200}{60}=125.6rad/sec

(b) Linear speed is given by v=\omega r=125.6\times 1.15=144.44m/sec

(c) Centripetal acceleration is given by a_c=\frac{v^2}{r}=\frac{144.44^2}{1.15}=18141.664m/sec^2

We know that g=9.81m/sec^2

So 18141.66m/sec^2=\frac{18141.664}{9.81}=1849.3031g

6 0
3 years ago
A 2320 pound roller coaster starts from rest and is launched such that it creates a 110 ft high hill with a speed of 65 mph. The
Sergeu [11.5K]

Answer: E = 941738.537J

Explanation:

to begin,

given that the mass = 2320 pound = 1052.334 kg

Δh = 110 ft = 33.528 m

given that  distance (d) = 1283 ft = 391.058 m

also the speed (v) is 65 mph = 29.058 m/s

force (F) = 87 pounds = 386.995 N

from our knowledge in work energy theory;

E = Fd + 1/2mv² + mgh

E = (386.995 × 391.058) + (1/2×1052.334×29.058²) + (1052.334×9.81×33.528)

E = 151337.491 + 444278.2 + 346122.84

E = 941738.537J

i hope this helps, cheers.

3 0
3 years ago
What type of fat may help lower the risk of heart disease
enyata [817]
Polyunsaturated fatty acids which is Omega-3 fatty acids.
8 0
3 years ago
Hey could i have some Help??
bagirrra123 [75]

Answer:

it is biology i think

4 0
3 years ago
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