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Andreyy89
3 years ago
15

Two protons and two neutrons are released as a result of this reaction.

Chemistry
2 answers:
Ierofanga [76]3 years ago
6 0

Answer:

The answer is A

Explanation:

Murljashka [212]3 years ago
3 0

<u>Answer:</u> The particle released in the given reaction is one alpha particle

<u>Explanation:</u>

In a nuclear reaction, the total mass and total atomic number remains the same.

For the given fission reaction:

^{222}_{86}\textrm{Rn}\rightarrow ^A_Z\textrm{X}+^{218}_{84}\textrm{Po}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

222 = A + 218

A = 4

  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

86 = Z + 84

Z = 2

The isotopic symbol of unknown element is _{2}^{4}\textrm{He}. Another name of helium atom is alpha particle.

Hence, the particle released in the given reaction is one alpha particle

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3 0
3 years ago
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A flexible container at an initial volume of 3.10 L contains 9.51 mol of gas. More gas is then added to the container until it r
Schach [20]

Answer:

49.09 moles of gas are added to the container

Explanation:

Step 1: Data given

Initial volume = 3.10 L

Number of moles gas = 9.51 moles

The final volume = 19.1 L

The pressure, temperature remain constant

Step 2: Calculate number of moles gas

V1/n1 = V2/n2

⇒with V1 = the initial volume of the gas = 3.10 L

⇒with n1 = the initial number of moles = 9.51 moles

⇒with V2 = the increased volume = 19.1 L

⇒with n2 = the final number of moles gas

3.10L / 9.51 moles = 19.1 L / n2

n2 = 58.6 moles

The new number of moles is 58.6

Step 3: calculate the number of moles gas added

Δn = 58.6 - 9.51 = 49.09 moles

49.09 moles of gas are added to the container

7 0
3 years ago
Ome fire extinguishers contain liquid carbon dioxide Suggest how carbon dioxide​
melisa1 [442]

Answer:

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8 0
3 years ago
When 0.49 g of a molecular compound was dissolved in 20.00 g of cyclohexane, the freezing point of the solution was lowered by 3
IRISSAK [1]

Answer: The molecular mass of this compound is 131 g/mol

Explanation:

Depression in freezing point:

\Delta T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

\Delta T_f = depression in freezing point  = 3.9^oC

k_f = freezing point constant  = 20.8^0C/m

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute = 0.49 g

w_1 = mass of solvent (cyclohexane) = 20.00 g

M_2 = molar mass of solute = ?

Now put all the given values in the above formula, we get:

(3.9)^oC=1\times (20.8^oC/m)\times \frac{(0.49g)\times 1000}{M_2\times (20.00g)}

M_2=131g/mol

Therefore, the molar mass of solute is 131 g/mol

7 0
3 years ago
4.00 g of sodium and 2.00 g of oxygen react according to the following balanced equation 4 Na + O2 → 2 Na2O Calculate the mass o
posledela
6.00g because it is a balanced equation
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3 years ago
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