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34kurt
3 years ago
9

PLEASE HELP ASAP

Chemistry
2 answers:
algol [13]3 years ago
6 0
Hey I’m sorry for using your question but I rlly need to ask sum and it won’t let me unless I answer to questions sorry again :(
Xelga [282]3 years ago
4 0

Answer:

Explanation:According to the law of conservation of mass (mass remains the same throughout a reaction), mass is conserved in this case. This can be proven by comparing the weight of two enclosed glass containers of the reaction. They will most likely have the same weight because the products the chemical reaction creates would most likely produce a gas that can be trapped if there is no opening in the glass container. To further investigate, compare the weights of the products of the reaction with an enclosed container to another container with no lid of the same reaction.

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The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation  </h3>

The elements in nature have several types of isotopes  

Isotopes are elements that have the same Atomic Number (Proton)  

Atomic mass is the average atomic mass of all its isotopes  

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu

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C₂H₄ + 3O₂ → 2CO₂ + 2H₂O If you start with 45.9 g of C₂H₄, and excess O₂, what mass of CO₂ will be produced?
hoa [83]

The mass of CO2 that would be produced is 144.03 g

From the equation of the reaction, the mole ratio of C2H4 input to CO2 produced is 1:2.

Recall that: mole = mass/molar mass

mole of 45.9 g C2H4 = 45.9/28.05

                                     = 1.6364 moles

Thus: equivalent moles of CO2 = 1.6364 x 2

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Mass of 3.2727 moles of CO2 = moles x molar mass

                                                = 3.2727 x 44.01

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More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults

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