Answer:
![\large \boxed{34.2\, ^{\circ}\text{C}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B34.2%5C%2C%20%5E%7B%5Ccirc%7D%5Ctext%7BC%7D%7D)
Explanation:
There are two heat transfers involved: the heat lost by the metal block and the heat gained by the water.
According to the Law of Conservation of Energy, energy can neither be destroyed nor created, so the sum of these terms must be zero.
Let the metal be Component 1 and the water be Component 2.
Data:
For the metal:
![m_{1} =\text{125 g; }T_{i} = 93.2 ^{\circ}\text{C; }\\C_{1} = 0.900 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$}](https://tex.z-dn.net/?f=m_%7B1%7D%20%3D%5Ctext%7B125%20g%3B%20%7DT_%7Bi%7D%20%3D%2093.2%20%5E%7B%5Ccirc%7D%5Ctext%7BC%3B%20%7D%5C%5CC_%7B1%7D%20%3D%200.900%20%5Ctext%7B%20J%24%5E%7B%5Ccirc%7D%24C%24%5E%7B-1%7D%24g%24%5E%7B-1%7D%24%7D)
For the water:
![m_{2} =\text{100 g; }T_{i} = 18.3 ^{\circ}\text{C; }\\C_{2} = 4.184 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$}](https://tex.z-dn.net/?f=m_%7B2%7D%20%3D%5Ctext%7B100%20g%3B%20%7DT_%7Bi%7D%20%3D%2018.3%20%5E%7B%5Ccirc%7D%5Ctext%7BC%3B%20%7D%5C%5CC_%7B2%7D%20%3D%204.184%20%5Ctext%7B%20J%24%5E%7B%5Ccirc%7D%24C%24%5E%7B-1%7D%24g%24%5E%7B-1%7D%24%7D)
![\begin{array}{rcl}\text{Heat lost by metal + heat gained by water} & = & 0\\q_{1} + q_{2} & = & 0\\m_{1}C_{1}\Delta T_{1} + m_{2}C_{2}\Delta T_{2} & = & 0\\\text{125 g}\times 0.900 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times\Delta T_{1} + \text{100 g} \times 4.184 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$}\Delta \times T_{2} & = & 0\\112.5\Delta T_{1} + 418.4\Delta T_{2} & = & 0\\112.5\Delta T_{1} & = & -418.4\Delta T_{2}\\\Delta T_{1} & = & -3.719\Delta T_{2}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5Ctext%7BHeat%20lost%20by%20metal%20%2B%20heat%20gained%20by%20water%7D%20%26%20%3D%20%26%200%5C%5Cq_%7B1%7D%20%2B%20q_%7B2%7D%20%26%20%3D%20%26%200%5C%5Cm_%7B1%7DC_%7B1%7D%5CDelta%20T_%7B1%7D%20%2B%20m_%7B2%7DC_%7B2%7D%5CDelta%20T_%7B2%7D%20%26%20%3D%20%26%200%5C%5C%5Ctext%7B125%20g%7D%5Ctimes%200.900%20%5Ctext%7B%20J%24%5E%7B%5Ccirc%7D%24C%24%5E%7B-1%7D%24g%24%5E%7B-1%7D%24%7D%20%5Ctimes%5CDelta%20T_%7B1%7D%20%2B%20%5Ctext%7B100%20g%7D%20%5Ctimes%204.184%20%5Ctext%7B%20J%24%5E%7B%5Ccirc%7D%24C%24%5E%7B-1%7D%24g%24%5E%7B-1%7D%24%7D%5CDelta%20%5Ctimes%20T_%7B2%7D%20%26%20%3D%20%26%200%5C%5C112.5%5CDelta%20T_%7B1%7D%20%2B%20418.4%5CDelta%20T_%7B2%7D%20%26%20%3D%20%26%200%5C%5C112.5%5CDelta%20T_%7B1%7D%20%26%20%3D%20%26%20-418.4%5CDelta%20T_%7B2%7D%5C%5C%5CDelta%20T_%7B1%7D%20%26%20%3D%20%26%20-3.719%5CDelta%20T_%7B2%7D%5C%5C%5Cend%7Barray%7D)
![\Delta T_{1} = T_{\text{f}} - 93.2 ^{\circ}\text{C}\\\Delta T_{2} = T_{\text{f}} - 18.3 ^{\circ}\text{C}](https://tex.z-dn.net/?f=%5CDelta%20T_%7B1%7D%20%3D%20T_%7B%5Ctext%7Bf%7D%7D%20-%2093.2%20%5E%7B%5Ccirc%7D%5Ctext%7BC%7D%5C%5C%5CDelta%20T_%7B2%7D%20%3D%20T_%7B%5Ctext%7Bf%7D%7D%20-%2018.3%20%5E%7B%5Ccirc%7D%5Ctext%7BC%7D)
![\begin{array}{rcl}\Delta T_{1} & = & -3.719\Delta T_{2}\\T_{\text{f}} - 93.2 ^{\circ}\text{C} & = & -3.719 (T_{\text{f}} - 18.3 ^{\circ}\text{C})\\T_{\text{f}} - 93.2 ^{\circ}\text{C} & = & -3.719T_{\text{f}} + 68.06 ^{\circ}\text{C}\\4.719T_{\text{f}} & = & 161.3 ^{\circ}\text{C}\\T_{\text{f}} & = & \mathbf{34.2 ^{\circ}}\textbf{C}\\\end{array}\\\text{The final temperature of the block and the water is $\large \boxed{\mathbf{34.2\, ^{\circ}}\textbf{C}}$}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Brcl%7D%5CDelta%20T_%7B1%7D%20%26%20%3D%20%26%20-3.719%5CDelta%20T_%7B2%7D%5C%5CT_%7B%5Ctext%7Bf%7D%7D%20-%2093.2%20%5E%7B%5Ccirc%7D%5Ctext%7BC%7D%20%26%20%3D%20%26%20-3.719%20%28T_%7B%5Ctext%7Bf%7D%7D%20-%2018.3%20%5E%7B%5Ccirc%7D%5Ctext%7BC%7D%29%5C%5CT_%7B%5Ctext%7Bf%7D%7D%20-%2093.2%20%5E%7B%5Ccirc%7D%5Ctext%7BC%7D%20%26%20%3D%20%26%20-3.719T_%7B%5Ctext%7Bf%7D%7D%20%2B%2068.06%20%5E%7B%5Ccirc%7D%5Ctext%7BC%7D%5C%5C4.719T_%7B%5Ctext%7Bf%7D%7D%20%26%20%3D%20%26%20161.3%20%5E%7B%5Ccirc%7D%5Ctext%7BC%7D%5C%5CT_%7B%5Ctext%7Bf%7D%7D%20%26%20%3D%20%26%20%5Cmathbf%7B34.2%20%5E%7B%5Ccirc%7D%7D%5Ctextbf%7BC%7D%5C%5C%5Cend%7Barray%7D%5C%5C%5Ctext%7BThe%20final%20temperature%20of%20the%20block%20and%20the%20water%20is%20%24%5Clarge%20%5Cboxed%7B%5Cmathbf%7B34.2%5C%2C%20%5E%7B%5Ccirc%7D%7D%5Ctextbf%7BC%7D%7D%24%7D)
Answer: 241.6 grams of CO2
Explanation: you take 84.3 grams C5H12 and divide it by 72.15 grams of C5H12(which is the molar mass) you take that answer and calculate the mols of CO2 by multiplying the 1.168 you got before and multiply it by 5. You take the answer you get from that and multiply it by the molar mass of CO2 and get the theoretical yield and then you just plug it in. 94= (x/257.02)x100 and solve to find x which is the actual yield.
chemical weathering and <span>mechanical weathering</span>
Photosynethesis, respiration, and combustion.