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kifflom [539]
2 years ago
11

Please help me with this problem!

Mathematics
1 answer:
MAXImum [283]2 years ago
6 0

Answer:

A

Step-by-step explanation:

It starts off at positive 3

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Someone help plss show work​
Mazyrski [523]

Answer:

Slope: \frac{3}{5}

Y-Intercept: (0,-5)

Step-by-step explanation:

1. To find the slope, we need to have the equation in slope-intercept form, which is y=mx+b. In this case, our equation is already in this form. m is what your slope is. In this case, our

2. To find the y-intercept we look at value b that is in y=mx+b. In this case, b is -5. So, our ordered pair is (0,-5).

4 0
2 years ago
Read 2 more answers
Apply the distributive property to factor out the greatest common factor.
Tanzania [10]
I’m pretty sure it’s 86, because you need to subtract 2 from the first side then you have 86 = X
5 0
2 years ago
Find the GCF of the numbers using lists of factors.<br> 27,45<br> 30,48<br> 28,48,64
Svetach [21]

Answer:

1.) 6

2.)6

3,)4

Step-by-step explanation:

I think these are the gcf of the numbers

6 0
3 years ago
PLEASE HELP PRE CAL!!
Len [333]

Answer:

Width = 2x²

Length = 7x² + 3

Step-by-step explanation:

∵ The area of a rectangle is 14x^{4}+6x^{2}

∵ Its width is the greatest common monomial factor of 14x^{4} and 6x²

- Let us find the greatest common factor of 14 , 6 and x^{4} , x²

∵ The factors of 14 are 1, 2, 7, 14

∵ The factors of 6 are 1, 2, 3, 6

∵ The common factors of 14 and 6 are 1, 2

∵ The greatest one is 2

∴ The greatest common factor of 14 and 6 is 2

- The greatest common factor of monomials is the variable with

   the smallest power

∴ The greatest common factor of x^{4} and  x² is x²

∴ The greatest common monomial factor of  14x^{4} and 6x² is 2x²

∴ The width of the rectangle is 2x²

To find the length divide the area by the width

∵ The area = 14x^{4}+6x^{2}

∵ The width = 2x²

∴ The length = ( 14x^{4}+6x^{2}) ÷ (2x²)

∵  14x^{4} ÷ 2x² = 7x²

∵ 6x² ÷ 2x² = 3

∴ ( 14x^{4}+6x^{2}) ÷ (2x²) = 7x² + 3

∴ The length of the rectangle is 7x² + 3

8 0
3 years ago
Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.
fgiga [73]

Answer:

  • QN = 3√7
  • OI = √7

Step-by-step explanation:

The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...

  DQ = (3 units)·3 = 9 units

  KO = (3 units)·1 = 3 units

Then the base lengths QN and OI can be found from the Pythagorean theorem:

  KI² = KO² +OI²

  4² = 3² +OI²

  OI = √(16 -9)

  OI = √7

  QN = 3·OI = 3√7

8 0
3 years ago
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