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kicyunya [14]
3 years ago
9

The pressure exerted on a sample of gas is 735 mm Hg with a volume of 375 mL and a temperature of 25 degrees Celsius. What would

the pressure of the gas be if the temperature was reduced to standard temperature and the volume was expanded to 500.0 mL?
Chemistry
1 answer:
Darina [25.2K]3 years ago
7 0

Answer:

= 498.13 mmHg

Explanation:

Using the combined gas law;

P1V1/T1 =P2V2/T2

in this case; P1 = 725 mmHg, V1 = 375 mL and T1 = 25°C + 273 = 298 K

P2 = ?  V2 = 500 mL and T2 (standard temperature) = 0°C + 273 = 273 K

P2 = P1V1T2/T1V2

     = (725 × 375 × 273)/(298 × 500)

     <u>= 498.13 mmHg </u>

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siniylev [52]
That is not a question/problem and makes no sense whatsoever
4 0
3 years ago
50 points!! i need 3 answers!!!
tester [92]
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3 0
3 years ago
Read 2 more answers
1. ___Mg +<br> O2 → __Mgo<br> What type of reaction is shown
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Explanation:

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8 0
3 years ago
Potassium iodide reacts with lead(II) nitrate in this precipitation reaction: 2 KI(aq) + Pb(NO3)2(aq) → 2 KNO3(aq) + PbI2(s) Wha
andrew11 [14]

Answer:

a. 174 mL

Explanation:

Let's consider the following reaction.

2 KI(aq) + Pb(NO₃)₂(aq) → 2 KNO₃(aq) + PbI₂(s)

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The molar ratio of KI to Pb(NO₃)₂ is 2:1. The moles of KI are:

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5 0
3 years ago
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vlada-n [284]
The others are wrong it's B. Condensation
5 0
3 years ago
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