Answer:
Explanation:
A conjugate base is formed when an acid in reaction with a base lose a proton H+.
For example if RCOOH that is an acid, reacts with water that is a base, the RCOOH loses an H+ and it becomes that is the conjugate base; and the water gains the H+ and become the conjugate acid, that is:
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The RCOO- is the conjugate base
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In this case the is the conjugate base
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The is the conjugate base
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The is the conjugate base.
Answer:
Energy absorbed by <u>Iron block</u> E (iron) = 460.5 J
Energy absorbed by <u>Copper block</u> E (Copper) = 376.8 J
Explanation:
To find the heat absorbed, we can use the formula as,
<em>q = m c ΔT</em>
Here, Mass = m = 10 g = 0.01 kg
ΔT = change in temperature = 400 - 300 = 100 K = 100 - 273 = -173 °C
c = specific heat capacity
c for iron = 460.5 J/kg K
c for copper = 376.8 J/kg K
Plugin the values in the above equation, we will get,
<em>q (iron) = 0.01 kg × 460.5 J/kg K × 100 K = 460.5 J</em>
<em>q (copper) = 0.01 kg × 376.8 J/kg K × 100 K = 376.8 J</em>
The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)
<u>Explanation:</u>
Given:
Specific Heat capacity of Iron= 0.450 J/ g °C
To Find:
Required Energy to raise the Temperature
Formula:
Amount of energy required is given by the formula,
Q = mC (ΔT)
Solution:
M = mass of the iron in g
So 3 kg = 3000 g
C = specific heat of iron = 0.450 J/ g °C [ from the given table]
ΔT = change in temperature = 25° C - 20°C = 5°C
Plugin the values, we will get,
Q = 3000 g × 0.450 J/ g °C × 5°C
= 6,750 J
So the energy required is 6,750 J.
Hello there.
<span>A roller coaster starts down a hill at 10 m/s. Three seconds later, its speed is 32 m/s. What is the roller coaster’s acceleration?
</span><span>7.3 m/s
</span>
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.
You get: BrO3 + N2H4 -> Br2 + N2 + H2O
# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2
Br:
Multiply the reactant (left) side by 2 to balance.
O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.
H:
The product side is now equal to 12. Multiply the reactant side by 3 to balance.
N:
Now you have to balance N because the reactant side has been risen. So multiply the product side by three as well.
You end up with the complete and balanced equation:
2BrO3 + 3N2H4 -> Br2 + 3N2 + 6H2O