Two objects attract each other with a gravitational force of magnitude 1.02 10-8 N when separated by 19.7 cm. If the total mass
of the two objects is 5.14 kg, what is the mass of each
2 answers:
Answer:
The two masses are 3.39 Kg and 1.75 Kg
Explanation:
The gravitational force of attraction between two bodies is given by the formula;
F = Gm₁m₂/d²
where G is the gravitational force constant = 6.67 * 10⁻¹¹ Nm²Kg⁻²
m₁ = mass of first object; m₂ = mass of second object; d = distance of separation between the objects
Further calculations are provided in the attachment below
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Answer:
The final velocity after the collision is 0.27 m/s.
Explanation:
Given that,
Mass of tiger, m = 0.195 kg
Initial speed of tiger model, v = 0.75 m/s
Mass of another clay model, m' = 0.335 kg
Initially, second model is at rest, v' = 0
We need to find the final velocity after the collision. It is a case of inelastic collision. Using the conservation of linear momentum as :
So, the final velocity after the collision is 0.27 m/s.
The average velocity is -4.17 m/s
Explanation:
The average velocity of a body is given by:
where
d is the displacement of the body
t is the time elapsed
For the student in this problem, we have:
Initial position:
Final position:
So the displacement is
The time elapsed is
t = 60 s
Therefore, the average velocity is
Where the negative sign means the student is moving towards the origin.
Learn more about average speed and velocity:
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