The function
f(x) is even
g(x) is neither even nor odd
h(x) is odd
Steps:
for an even function it holds that f(-x) = f(x):
f(-x) = (-1)^6 x^6 - (-1)^4 x^ 4 = x^6 - x^4 = f(x) => f is even
for an odd h(x) it holds that h(-x) = -h(x):
It is easy to show that g(x) does not match any of the two possibilities above.
"A. 4x^4 is the answer so try that."
Answer:
can anyone explain step by step how to fiquire this out please .. sons teacher isnt helping
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
1. yes
2. no, 4.82 x 10^4
3, no, 9.9 x 10^-4
4. no, 3.6 x 10^6
5. yes
6. no, 7.8 x 10^-4
F•h(7)=(-7+1)-1=-7 when you have a function that looks like foh, you basically plug the equation of h in for the x value in the equation of f
