Answer:
The image distance is 30 cm
image height = - 5 cm
Explanation:
The formula for calculating the image distance is expressed as
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
From the information given,
u = 30
f = 15
By substituting these values into the formula,
1/15 = 1/30 + 1/v
1/v = 1/15 - 1/30 = (2 - 1)/30 = 1/30
Taking the reciprocal of both sides,
v = 30
The image distance is 30 cm
magnification = image height/object height = - v/u
Given that object height = 5 cm, then
image height/5 = - 30/30 = - 1
image height = - 5 * 1
image height = - 5 cm
The electron fell down to the lowest orbital it could inhabit
The average<span> speed of an object is defined as the distance traveled divided by the time elapsed. </span>Velocity<span> is a vector quantity, and </span>average velocity<span> can be defined as the displacement divided by the time. Hope this answers the question. Have a nice day.</span>
The correct answer is: [A]: "TRUE" .
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Answer:
false
Explanation: all compounds are electrically neutral.