Answer:
A charge q1=7.0mc is located at the origin and a second charge q2=-5.0mc is located on the x axis, 0.3m the origin find the electric field at the point p which he's coordinates (0,0.40)m
Answer:

Explanation:
Approximately, we can use the ideal gas law, below we see how we can deduce the density from general gas equation. To do this, remember that the number of moles n is equal to
, where m is the mass and M the molar mass of the gas, and the density is
.
For air
and 
So, 

Answer:
I did not what is it about?
Answer:
Yes
Explanation:
As we know that octane number resist the engine from knocking.If knocking can prevent that automatically the performance of engine will increases.If octane number is 100 then it means that knocking tendency in the engine is zero.So higher the octane number better will the performance of the engine.
Generally octane number is 87 but for premier gasoline is 92 or 93.
So we can say that if octane number is 93 then car will give better performance
A is the answer for the sentence