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Fudgin [204]
3 years ago
5

How much heat Q H QH does a heat pump with a coefficient of performance of 2.10 2.10 deliver when supplied with 1.82 kJ 1.82 kJ

of electricity?
Physics
1 answer:
valina [46]3 years ago
4 0

The operating coefficient or performance coefficient of a heat pump is the ratio between the heating or cooling provided and the electricity consumed. The higher coefficients are equivalent to lower operating costs. The coefficient can be greater than 1, because it is a percentage of the output: losses, other than the thermal efficiency ratio: input energy. Mathematically can be written as,

\text{Coefficient of performance} = \frac{\text{Heat extracted}}{\text{Electrical energy supplied}}

COP = \frac{Q}{E}\rightarrow Q =COP\times E

Replacing,

Q = 2.1\times 1.82kJ

Q = 3.822kJ

Therefore the heat is 3.822kJ

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lianna [129]
The air movements toward the equator are called trade winds, which are warm, steady breezes that blowalmost continuously. The Coriolis Effect makes the trade winds appear to be curving to the west, whether they are traveling to the equator from the south or north. Answer trade wind
7 0
3 years ago
Recently, astronomers have observed stars and other objects that orbit the center of the Milky Way Galaxy farther out than our S
Lesechka [4]

Answer:

That scenario can be explained by the idea of the contribution of dark matter on that point.

Explanation:

It can be explained through the idea of dark matter, this one was born to explain why stars (or any object) that were farther for the supermassive black hole in the center of the Milky Way galaxy didn't decrease it rotational velocity as it was expected according to equation 1.

v = \sqrt{\frac{G M}{r}}  (1)

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3 years ago
A penudulum has a period of 6.5s what is its frequency
Sergio039 [100]

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Plug in the values and u arrive at the answer

5 0
3 years ago
In a ballistics test, a 24 g bullet traveling horizontally at 1200 m/s goes through a 31-cm-thick 320 kg stationary target and e
Zanzabum

Answer:

The  velocity is  v_t  =  0.02175 \  m/s

Explanation:

From the question we are told that

   The  mass of the bullet is  m_b  =  0.024 \  kg

    The initial speed of the bullet is  u_b  =  1200 \  m/s

   The mass of the target is  m_t  =  320 \  kg

    The  initial velocity of target is  u_t  =  0  \ m/s

    The  final velocity of the bullet is  is  v_b  =  910 \  m/s

   

Generally according to the law of momentum conservation we have that

      m_b *  u_b  +  m_t *  u_t  =  m_b *  v_b  +  m_t  *  v_t

=>   0.024  *  1200  +  320 *  0  =  0.024 *  910   +  320  *  v_t

=>    v_t  =  0.02175 \  m/s

3 0
3 years ago
The same pipe is used to carry both air and water. For the same fluid velocity and friction factor for the air and water flows:
VladimirAG [237]

Answer:

the pressure drop for the water flow is greater than that for the air flow.

Explanation:

Detailed analysis of the problem is show below.

4 0
3 years ago
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