1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
barxatty [35]
3 years ago
12

Which statements are true for two oppositely charged, isolated parallel plates: C=capacitance, U=stored energy (Q and -Q = charg

e on the plates). Note: Isolated plates can not lose their charge.
1. Inserting a dielectric decreases U.

2. When the distance is doubled, C increases.

3. Increasing the distance increases the Electric field.

4. Inserting a dielectric increases Q.

5. Inserting a dielectric increases C.

6. When the distance is halved, Q stays the same.

7. When the distance is doubled, U increases.
Physics
1 answer:
vlada-n [284]3 years ago
7 0

Answer:

Explanation:

1) True. The stored energy (U) is proportional to the electric field strength (E). The electric field strength decreases when a dielectric is introduced hence inserting a dielectric decreases U.

2) False. From the formula C=\frac{Q}{V}=\frac{Q}{Vd}, capacitance is inversely proportional to distance hence if the distance is doubled, capacitance decreases.

3) False. As the distance between the electric field and the object increases, its electric field decreases.

4) False. If a dielectric is inserted, the plates are further separated. Q stays the same.

5) True. The electric field strength decreases when a dielectric is introduced and  capacitance is inversely proportional to electric field hence Inserting a dielectric increases C

6) True. If a dielectric is inserted, the plates are further separated. Q stays the same.

7) True. When the distance is doubled, U increases

You might be interested in
The ray diagram shows a vase that is placed beyond the center of curvature of a concave mirror. Which best describes how the ima
Law Incorporation [45]
To get to know the characteristics of the image formed, you complete the ray diagram. 
When the object is place beyond C the image formed is usual smaller than the object. 
The image is also inverted. 
∴The best statement that describes the image is <span>D.) It will be smaller than the vase and inverted</span>
3 0
3 years ago
Read 2 more answers
A wind turbine takes in energy from wind with the goal of converting it into electrical energy. Much of the wind energy is also
kondor19780726 [428]

The efficiency of the turbine is 50%.

The given parameters:

  • <em>Kinetic energy of the wind, E = 3000 J</em>
  • <em>Output electrical energy, E(out) = 750 J</em>
  • <em>Energy lost to heat, E(lost) = 750 J</em>
  • <em>Kinetic energy of the turbine, E(in) = ?</em>

The kinetic energy of the turbine which is the input energy is calculated as follows;

E(in) = 3000 - (750 + 750)

E(in) = 1500 J

The efficiency of the turbine is calculated as follows;

E_f_f = \frac{E_{(out)}}{E_{(in)}} \times 100\%\\\\E_f_f = \frac{750}{1500} \times 100\%\\\\E_f_f = 50  \%

Thus, the efficiency of the turbine is 50%.

Learn more about efficiency of turbine here: brainly.com/question/2009210

5 0
3 years ago
The moon’s rotational period and revolution period are equal. What is the result of this? Enter your answer in the space provide
beks73 [17]

Answer The Moon has synchronous rotation: it's rotation period is the same as its period of revolution

Explanation:

The Moon has synchronous rotation: it's rotation period is the same as its period of revolution

5 0
4 years ago
A shooting star is actually the track of a meteor, typically a small chunk of debris from a comet that has entered the earth's a
s2008m [1.1K]

Answer:

A. Power generated by meteor = 892857.14 Watts

Yes. It is obvious that the large amount of power generated accounts for the glowing trail of the meteor.

B. Workdone = 981000 J

Power required = 19620 Watts

Note: The question is incomplete. A similar complete question is given below:

A shooting star is actually the track of a meteor, typically a small chunk of debris from a comet that has entered the earth's atmosphere. As the drag force slows the meteor down, its kinetic energy is converted to thermal energy, leaving a glowing trail across the sky. A typical meteor has a surprisingly small mass, but what it lacks in size it makes up for in speed. Assume that a meteor has a mass of 1.5 g and is moving at an impressive 50 km/s, both typical values. What power is generated if the meteor slows down over a typical 2.1 s? Can you see how this tiny object can make a glowing trail that can be seen hundreds of kilometers away? 61. a. How much work does an elevator motor do to lift a 1000 kg elevator a height of 100 m at a constant speed? b. How much power must the motor supply to do this in 50 s at constant speed?

Explanation:

A. Power = workdone / time taken

Workdone = Kinetic energy of the meteor

Kinetic energy = mass × velocity² / 2

Mass of meteor = 1.5 g = 0.0015 kg;

Velocity of meteor = 50 km/s = 50000 m/s

Kinetic energy = 0.0015 × (50000)² / 2 = 1875000 J

Power generated = 1875000/2.1 = 892857.14 Watts

Yes. It is obvious that the large amount of power generated accounts for the glowing trail of the meteor.

B. Work done by elevator against gravity = mass × acceleration due to gravity × height

Work done = 1000 kg × 9.81 m/s² × 100 m

Workdone = 981000 J

Power required = workdone / time

Power = 981000 J / 50 s

Power required = 19620 Watts

Therefore, the motor must supply a power of 19620 Watts in order to lift a 1000 kg to a height of 100 m at a constant speed in 50 seconds.

6 0
3 years ago
The voltage applied across a given parallel-plate capacitor is doubled. How is the energy stored in the capacitor affected?
ikadub [295]

Answer:

The energy stored in the capacitor quadruples its original value.

Explanation:

The energy stored in a capacitor is given by the equation

U=\frac{1}{2}CV^2

where

C is the capacitance

V is the voltage across the plates

The capacitance, C, depends only on the properties of the capacitor, so it does not change when the voltage applied is changed.

Instead, in this problem the voltage applied is doubled:

V' = 2V

So the new energy stored is

U'=\frac{1}{2}C(2V)^2=4(\frac{1}{2}CV^2)=4U

so, the energy stored has quadrupled.

8 0
3 years ago
Other questions:
  • A spaceship flies from Earth to a distant star at a constant speed. Upon arrival, a clock on board the spaceship shows a total e
    10·1 answer
  • The temperature at the surface of the Sun is approximately 5,200 K, and the temperature at the surface of the Earth is approxima
    6·1 answer
  • A soccer player kicks a ball, giving it an initial velocity of 9.0 m/s in the positive x- direction. Because of the wet grass an
    7·1 answer
  • Which two factors affect the force between two masses, according to the universal law of gravitation? the masses of the objects
    11·1 answer
  • Structures that trap light energy and perform photosynthesis
    13·1 answer
  • A 600-g mass traveling at 8.0 m/s undergoes a head-on elastic collision with a 200-g mass traveling toward it also at 8.0 m/s. W
    9·1 answer
  • Select the correct answer.
    7·2 answers
  • The ratio between the velocity of microwaves to the velocity of gamma ray in air is_____ .
    10·1 answer
  • Simple physics question
    10·1 answer
  • What would make oppositely charged objects attract each other more?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!