Number of moles in the K2SO4 sample
= (16/1000)*1.04= 0.01664 mol
Number of moles in the Ba(NO3)2 sample
= (14.3/1000*0.880)= 0.01258 mol
Since the reaction is a 1:1 ratio between the two reactants, the limiting reagent is the one containing a smaller number of moles, namely Ba(NO3)2.
The molecular mass of BaSO4 is 137.3+(32.06+4*16.00)=233.4
Therefore the theoretical yield of Barium Sulphate is
233.4*0.01258=2.937 g
Actual yield = 2.60 g (given)
Therefore the percentage yield = 2.60/2.937=88.54%
Answer:
1. the limiting reagent is Barium Nitrate (Ba(NO3)2)
2. the theoretical yield is 2.94 g
3. the percentage yield is 88.5%
I apologize for the mistake previous to this update.
Extrusive rock because it takes longer to cool, making the crystal size larger
B, but keep in mind the element sodium is very reactive (though table salts, on the other hand, are not).
Answer:
1.070MKCl
Explanation:
So we know that the original formula is M= n/L (n being moles of solute, L being liters of solvent)
Since we do not have liters in this problem, we would need to convert milliliters to liters
<u>213 mL= 0.213 L</u>
We then see that we do not have moles, but we do have a mass, being <u>17.0 g.</u> we would need to convert these grams to moles, giving us <u>0.228 mol.</u>
Then, you would plug in <u>0.228 for your n</u>, and now you are ready to solve your original formula, plugging everything in.
M=n/L
M=0.228 mol/0.213L
M= 1.070MKCl
I know this was long, but I hope this helps (:
