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elixir [45]
3 years ago
8

Help! Can someone please explain how to do this?

Physics
1 answer:
Vladimir79 [104]3 years ago
7 0
I believe the answer is B
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If you run a complete loop around an outdoor track of length 400 m in 100 s, find your(a) average velocity and (b) average speed
laila [671]

Answer:

a) 0 m/s

b) 4 m/s

Explanation:

The average velocity would end up being 0 because it is displacement over time and the displacement here is 0. However, speed is total distance over time which here is 400/100 so it is 4.

5 0
3 years ago
A 22.0 ohm and 75.0 ohm resistor are in parallel, connected to a 5.00 v battery. how much current flows out of the battery
Julli [10]

Answer:

294 mAmps

Explanation:

The two resistors are equal to   22 * 75 / ( 22+ 75) = 17.01 ohm

V = IR

V/R = I

5 / 17.01 = .294 A

5 0
2 years ago
During a collision, a 63.9-kilogram driver of a car moving at 24 m/s is brought to rest by an inflating airbag in 1.2 seconds. W
kaheart [24]

Hi there!

We can use impulse for this situation:

I = Δp = mΔv

Impulse = Force × time, so:

I = 63.9(24) = 1533.6 Ns

Find force by dividing by time:

I/t = 1533.6/1.2 = 1278 N

7 0
2 years ago
A 30.0 kg child, initially at rest, slides down a 2.0 m tall slide. The child reaches the bottom of the slide with a speed of 6
HACTEHA [7]

Answer:

Explanation:

Total energy is constant

E = mgh + ½mv² + Fd

At the top of the slide, all energy is potential

E = mgh + 0 + 0

At the bottom of the slide, all potential energy has converted to kinetic and work of friction.

mgh = ½mv² + W

W = mgh - ½mv²

W = 30.0[(9.81)(2.0) - ½6²]

W = 48.6 J

5 0
2 years ago
QUESTION 4.
n200080 [17]

Answer:

Follows are the solution to this question:

Explanation:

Please find the correct question in the attachment file.

Let:

\overrightarrow{R}= R_i\hat{i}+R_j\hat{j}+R_k\hat{k}\\\\\overrightarrow{S}= S_i\hat{i}+S_j\hat{j}+S_k\hat{k}\\\\

Calculating the value of  \overrightarrow{R} \times \overrightarrow{S}:

\to \left | \begin{array}{ccc}\hat{i}&\hat{j}&\hat{K}\\R_i&R_j&R_k\\S_i&S_j&S_k\end{array}\right | = \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j]

Calculating the value of \overrightarrow{R}  \cdot (\overrightarrow{R} \times \overrightarrow{S}):

\to (R_i\hat{i}+R_j\hat{j}+R_k\hat{k}) \cdot ( \hat{i}[R_j S_k-S_jR_k]-\hat{j}[R_i S_k-S_iR_k]+\hat{k}[R_i S_j-S_iR_j])

by solving this value it is equal to 0.

8 0
3 years ago
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