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3 years ago

Electronic configuration of magnessium

Chemistry

1 answer:

zepelin [54]3 years ago

7 0

Answer:

[Ne] 3 $s^{2}$

Explanation:

You can alternatively write it as 1 $s^{2}$ 2 $s^{2}$ 2 $p^{6}$ 3 $s^{2}$ , but since noble gasses like neon are stable, we simply write their letter and then the configuration that goes after them.

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34.1 mg NaCl in 117.3 mL of solution

Solnce55 [7]

The molarity of the solution will be 4.97 M.

<h3>What is molarity?</h3>

It is the number of moles of solutes per 1 liter of solvent or solution.

Mole of 34.1 g NaCl = 34.1/58.44 = 0.5835 mol

117.3 mL = 117.3/1000 = 0.1173 L

Molarity of the solution = 0.5835/0.1173 = 4.97 M

More on molarity can be found here: brainly.com/question/2817451

#SPJ1

6 0

2 years ago

If 335 g water at 35.5C loses 5750 J of heat, what is the final temperature of the water?

White raven [17]

Answer:

The final temperature is 39.58 degree Celsius

Explanation:

As we know

Q = m * c * change in temperature

Specific heat of water (c) = 4.2 joules per gram per Celsius degree

Substituting the given values we get -

5750 = 335 * 4.2 * (X - 35.5)

X = 39.58 degree Celsius

3 0

3 years ago

CsH«N2(l) + CuCl(s)

bulgar [2K]

0.498 moles of copper(II) phthalocyanine would be produced by

the complete cyclotetramerization of 255 grams of phthalonitrile in the

presence of excess copper(ll) chloride.

<em>Copper(ll) phthalocyanine (Cu(C₃₂H₁₆N₈)) is produced by the cyclotetramerization of phthalonitrile (C₈H₄N₂) according to the following reaction: 4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g) How many moles of copper(II) phthalocyanine would be produced by the complete cyclotetramerization of 255 grams of phthalonitrile in the presence of excess copper(II) chloride?</em>

Let's consider the following balanced equation.

4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g)

The molar mass of C₈H₄N₂ is 128.13 g/mol. The moles corresponding to 255 g of C₈H₄N₂ are:

$255 g \times \frac{1mol}{128.13 g} = 1.99 mol$

The molar ratio of C₈H₄N₂ to Cu(C₃₂H₁₆N₈) is 4:1. The moles of Cu(C₃₂H₁₆N₈) produced from 1.99 moles of C₈H₄N₂ are:

$1.99 mol C_8H_4N_2 \times \frac{1molCu(C_{32}H_{16}N_8)}{4mol C_8H_4N_2} = 0.498 mol Cu(C_{32}H_{16}N_8)$

0.498 moles of copper(II) phthalocyanine would be produced by

the complete cyclotetramerization of 255 grams of phthalonitrile in the

presence of excess copper(ll) chloride.

You can learn more about stoichiometry here: brainly.com/question/22288091

8 0

2 years ago

Which if the following is true about scientific theory?

WITCHER [35]

Theory can be changed to explain new observations or experimental results

6 0

3 years ago

What it is the total length of two pieces of rubber tubing which are 7.69 cm and 4.028 cm in length? Express this answer to the

Brilliant_brown [7]

The corrects answer it 9. 45

6 0

3 years ago