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3 years ago

Given the molecular formula, C9H13N, the correct empirical formula is

Chemistry

1 answer:

Lesechka [4]3 years ago

7 0

Answer:

C9H13N

Explanation:

Since there is no common factor besides 1, the formula is already the empirical formula for this compound.

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3 years ago

A certain half-reaction has a standard reduction potential E⁰ʀᴇᴅ = 0.83 V. An engineer proposes using this half-reaction at the

Leviafan [203]

Answer:

For 1: The minimum standard electrode potential at cathode is -0.03 V

For 2: The maximum standard electrode potential at cathode is 1.63 V

Explanation:

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

We are given:

$E^o_{cell}$ = Standard electrode potential of the cell = 0.80 V

For 1:

To make the standard reduction potential at the cathode minimum, we take the standard reduction potential at anode as (0.83 V)

Putting values in above equation, we get:

$0.80=E^o_{cathode}-(0.83)\\\\E^o_{cathode}=0.80-0.83=-0.03V$

Hence, the minimum standard electrode potential at cathode is -0.03 V

For 2:

To make the standard reduction potential at the cathode maximum, we take the standard reduction potential at anode as (-0.83 V)

Putting values in above equation, we get:

$0.80=E^o_{cathode}-(-0.83)\\\\E^o_{cathode}=0.80+0.83=1.63V$

Hence, the maximum standard electrode potential at cathode is 1.63 V

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3 years ago