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MatroZZZ [7]
3 years ago
6

A 0.05 kg ball is attached to the end of a 0.5 m long string. The ball is spun around a circle with a period of 0.20 s. What is

the tension force in the string? ​
Physics
1 answer:
Gekata [30.6K]3 years ago
4 0

The ball spins once around the circle in 0.20 s, meaning it travels a distance equal to its circumference in that time, giving it a linear speed of

<em>v</em> = (2<em>π</em> (0.5 m)) / (0.20 s) = 5<em>π</em> m/s ≈ 15.708 m/s

Use this compute the magnitude of the centripetal acceleration <em>a</em> :

<em>a</em> = <em>v</em>²/ (0.5 m) = 50<em>π</em>² m/s² ≈ 493.48 m/s²

Use Newton's second law to compute the mangitude of the tension <em>F</em> in the string:

<em>F</em> = (0.05 kg) <em>a</em> = 5/2 <em>π</em>² N ≈ 24.674 N ≈ 25 N

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