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marysya [2.9K]
3 years ago
12

What is the force on a 1025 kg elevator that is falling freely at 9.8 m/sec 2?

Physics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

<h2><u>Given </u><u>:</u><u>-</u></h2>
  • Mass = 1025 kg
  • Acceleration = 9.8 m/s²
<h2><u>To </u><u>Find</u><u> </u><u>:</u><u>-</u></h2>

Force

<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>

We know that

F = mg

F = 1025 × 9.8

F = 10,045 N

Or,

10045/1000 = 10.045 Kilo Newton

\\

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