8. complementary angles = 90°
3x+3+10x-4 = 90
13x-1 = 90
13x = 91
so x = 91/13= 7
then K = 3(7)+3 = 24°
so L = 10(7)-4 = 70-4 = 66°
9. P is three less than twice of Q
so P = 2Q-3
supplementary angles = 180°
P+Q = 180
(2Q-3)+Q = 180
3Q-3 = 180
3Q = 183
so Q = 183/3 = 61°
then P= 2(61)-3 = 122-3 = 119°
10. B is two more than three times of C so B= 3C+2
complementary angles = 90°
B+C= 90
(3C+2)+C=90
4C+2=90
4C= 88
so C= 22°
then B = 3(22)+2= 66+2 = 68°
Answer:
1. Two ribbons, A and B. One third of A is equal to all of B. Draw a tape diagram to show the ribbons.
2. Half Robert’s piece of wire is equal to 2/3 of Maria’s wire. The total length of their wires is 10 feet. How much longer is Robert's wire than Maria's?
3. Half Sarah’s wire is equal to 2/5 of Daniel’s. Chris has 3 times as much as Sarah. In all, their wire measures 6 ft. How long is Sarah’s wire in feet?
Answer:
Solution : 8i
Step-by-step explanation:
We can use the trivial identities cos(π / 2) = 0, and sin(π / 2) = 1 to solve this problem. Let's substitute,
= 
And of course 1i = i, so we have the expression 8(0 + i ). Distributing the " 8, " 8( 0 ) = 0, and 8(i) = 8i, making the fourth answer the correct solution.
Set up a proportion
160 mi/ 3.2 hrs ≈ 300 mi/x hrs
cross multiply and solve for x and you get x≈6
It will take them 6 hours
748 student tickets were sold.
Step-by-step explanation:
Given,
Number of tickets sold = 1360
Revenue generated = $13328
Cost of each student ticket = $8
Cost of each non student ticket = $12
Let,
x be the number of student tickets sold
y be the number of non student tickets sold
According to given statement;
x+y=1360 Eqn 1
8x+12y=13328 Eqn 2
Multiplying Eqn 1 by 12

Subtracting Eqn 2 from Eqn 3

Dividing both sides by 4

748 student tickets were sold.
Keywords: linear equation, elimination method
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