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DedPeter [7]
3 years ago
10

On the computer, we can only approximate the true Fourier transform because of the need for both time and frequency sampling. Be

cause of the limited frequency resolution, the frequency of a cosine may not line up exactly at a frequency sample, but vou'll still get a peak around that frequency. Assuming that vou sample the signal with fs-8000 Hz, and take its Fourier transform using an FFT with 4096 points, what is the value (in Hz) of the FFT frequency bins closest to the two frequencies of the sinusoids (941 and 1336 Hz)
Physics
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:

hello your question is incomplete below is the missing part

Consider the sum of sinusoids de (t) = sin(24(941)t) + sin(27(1336)t)

answer : Value of DFT frequency = 684 Hz

Explanation:

Given data:

sample signal ( Fs ) = 8000 Hz

Fourier transform using an FFT with 4096 points

<u>Determine the value of DFT frequency bins closest to the two frequencies of the sinusoids ( 941 and 1336 Hz )    ( in HZ )</u>

fs = 8000 Hz

4096 parts are divided with a gap of Fs/N

 attached below is the detailed solution

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