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andrey2020 [161]
3 years ago
5

A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x directi

on. After the collision, the 1.00 kg object moves with a velocity of 4.00 m/s in the - x direction. How much kinetic energy was lost during the collision?
Physics
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:

The amount of kinetic energy lost during the collision is 60.75 J

Explanation:

The given parameters are;

The mass of the object moving in the +x direction, m₁ = 1.00 kg

The velocity of the object moving in the +x direction, v₁ = 10.0 m/s

The mass of the object moving in the -x direction, m₂ = 1.50 kg

The velocity of the object moving in the +x direction, v₂ = 5.00 m/s

The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

The direction of motion of the 1.00 kg mass after collision = -x direction

The total initial kinetic energy of the system, K.E._{total \ initial} = 1/2·m₁·v₁² + 1/2·m₂·v₂²

∴ K.E._{total \ initial}  = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J

The final kinetic energy of the system, K.E._{final}  = 1/2·m₁·v₃²

K.E._{final} = 1/2×1.00×4² = 8 J

The amount of kinetic energy lost during the collision, \Delta K.E._{system} is given as follows;

\Delta K.E._{system} =  K.E._{final} -K.E._{total \ initial} = 8 J - 68.75 J = -60.75 J

The amount of kinetic energy lost during the collision = 60.75 J.

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Find the potential energy of a 2 kg ball 15 m in the air.
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Answer:

294.3 Joules

Explanation:

2kg*9.81m/s^2*Δ15=294.3J

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3 years ago
While walking past a construction site, a person notices a pipe sticking out of a second floor window with water pouring out. As
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Answer:

Its diameter increases as it flows down from the pipe. Assuming laminar flow for the water, then Bernoulli's equation can be applied.

P1-P2 + (rho)g(h1 - h2) + 1/2(rho)(v1² - v2²) = 0

Explanation:

P1 = P2 = atmospheric pressure so, P1 - P2 = 0

h1 is greater than h2 so h1-h2 is positive. Rearranging the equation above 2{ (rho)g(h1-h2) + 1/2(rho)v1²}/rho = v2²

From the continuity equation for fluids

A1v1 = A2v2

v2 = A1v1/A2

Substituting into the equation above

(A1v1/A2)² = 2{ (rho)g(h1-h2) + 1/2(rho)v1²}/rho

Making A2² the subject of the formula,

A2² = (A1v1)²× rho/(2{ (rho)g(h1-h2) + 1/2(rho)v1²}

The denominator will be greater than the numerator and as a result the diameter of the flowing stream decreases.

Thank you for reading.

4 0
3 years ago
(a) An object that has a small mass and an object that has a large mass have the same momentum. Which object has the largest kin
Iteru [2.4K]

Answer:

A) The smaller object; B) The larger object

Explanation:

A) Lets say the small object is 2 kg and the large one is 6 kg. Lets say they also have 30 kg*m/s of momentum each. The small object would have 15 m/s velocity and the large would have 5 m/s.

Now for kinetic energy(.5*m*v²), the small object is .5*2*15², which is 225 J

The large object is .5*6*5², which is 75 J, so the smaller object has more Kinetic energy. Since velocity is squared, it is more important than how large mass is.

B) Same masses as part A. Lets say the kinetic energy is 45 J for both of them. For the small object, 45=.5*2*v²

.5*2 is 1, so 45/1 is 45. Take the square root and we get v= 6.71 m/s

For the large object, 45=.5*6*v²

.5*6 is 3, so 45/3 is 15. Take the square root and we get v=3.87 m/s

Now we plug the velocities into p=mv

For the small object, p=2*6.71, which gives us p=13.42 kg*m/s

For the large object, p=6*3.87, which gives us p=23.22 kg*m/s

The larger object has the larger momentum.

Hope this helps

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b. sunlight, glucose, water, altra-violet ray as catalyst

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