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3 years ago

An object moving with a speed of 48 m/s has a kinetic energy of 4,632 J, what is the mass, in kg,

Physics

1 answer:

pickupchik [31]3 years ago

7 0

Answer:

4.0 Kg

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 48 m/s

Kinetic energy (KE) = 4632 J

Mass (m) =?

Kinetic energy can be defined as the energy possess by a moving object. Mathematically, it is expressed as:

KE = ½mv²

Where

KE => kinetic energy

m => mass of object

v => velocity

With the above formula, we can obtain the mass of the object as follow:

Velocity (v) = 48 m/s

Kinetic energy (KE) = 4632 J

Mass (m) =?

KE = ½mv²

4632 = ½ × m × 48²

4632 = ½ × m × 2304

4632 = m × 1152

Divide both side by 1152

m = 4632 / 1152

m = 4.0 Kg

Therefore, the mass of the object is 4.0 Kg

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butalik [34]

Answer:

time = 8.3333 minutes.

Explanation:

distance between earth and sun = 1.5 * $10^{8}km$

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convert the distance unit from km to m so we can have uniform units.

distance between earth and sun = 1.5 * $10^{8}*1000$ m

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speed = distance /time

time = distance / speed

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A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the g

levacccp [35]

The actual weight of the gas = apparent weight + weight.

The actual weight = $W_{A}$ + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = $W_{A}$

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Learn more about density here: brainly.com/question/406690

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2 years ago

What does keplers second law of planetary monition imply

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3 years ago

Read 2 more answers

The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (o

LUCKY_DIMON [66]

Answer:

The average impact force is 12000 newtons.

Explanation:

By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:

$\bar F \cdot \Delta t = m \cdot (v_{2}-v_{1})$ (1)

Where:

$\bar F$ - Average impact force, in newtons.

$\Delta t$ - Duration of the impact, in seconds.

$m$ - Mass of the sledge hammer, in kilograms.

$v_{1}$ , $v_{2}$ - Initial and final velocity, in meters per second.

If we know that $\Delta t = 0.0020\,s$ , $m = 4\,kg$ , $v_{1} = -6\,\frac{m}{s}$ and $v_{2} = 0\,\frac{m}{s}$ , then we estimate the average impact force is:

$\bar F = \frac{m\cdot (v_{2}-v_{1})}{\Delta t}$

$\bar F = 12000\,N$

The average impact force is 12000 newtons.

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3 years ago