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alina1380 [7]
3 years ago
9

If yttrium loses three electrons to be similar to Krypton (to try and become Royal), what type of ion does it become.

Chemistry
1 answer:
zhenek [66]3 years ago
5 0

Answer:

.

Explanation:

Did u get ur answer dear?

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What is the molar mass of CH4 (C=12.011 amu H = 1.008 amu)
never [62]

Answer:

16.05 amu

Explanation:

12.011 rounds to about 12.01 and 1.008 rounds to about 1.01 so when adding you'd do [12.01 + (1.01×4)]= 16.05

6 0
3 years ago
What kind of bond is present in HCI? (Use the electronegativity values from
Snezhnost [94]
The answer is
D. Covalent bond
Hope this helps you have a great day.
8 0
3 years ago
How many moles are in 12 liters of Cl2?
RoseWind [281]

Answer:

\boxed {\boxed {\sf 0.54 \ mol \ Cl_2}}

Explanation:

A mole is any quantity of a substance that contains 6.02 × 10²³ particles. At standard temperature and pressure, or STP, 1 mole of as is equal to 22.4 liters. This is true for any gas, regardless of the specific kind.

Although it is not specified, we can assume this gas is at STP. Let's set up a ratio using this information: 22.4 L/mol

\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Multiply by the given number of liters: 12

12 \ L \ Cl_2 *\frac {22.4 \ L \ Cl_2}{1 \ mol \ Cl_2}

Flip the ratio so the liters of chlorine cancel.

12 \ L \ Cl_2 * \frac {1 \ mol \ Cl_2}{22.4 \ L \ Cl_2}

12  * \frac {1 \ mol \ Cl_2}{22.4 }

\frac {12}{22.4 }  \ mol \ Cl_2

0.53571428571 \ mol \ Cl_2

The original measurement of liters has 2 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 0.53<u>5</u>71428571

The 5 in the thousandth place tells us to round the 3 up to a 4.

0.54 \ mol \ Cl_2

12 liters of chlorine gas at STP is approximately <u>0.54 moles of chlorine gas.</u>

8 0
3 years ago
The Ksp for BaCO3 is 5.1x10^-9. how many grams of BaCO3 will dissolve in 1000ml of water
Amanda [17]

Answer:

= 0.014 g of BaCO3

Explanation:

Let x = mol/L of BaCO3 that dissolve.  

This will give;

x mol/L Ba2+ and x mol/L CO32-  

But;

Ksp = 5.1x10^-9.

Therefore;

Ksp = 5.1 x 10^-9 = (x)(x)  

Thus;

x = molar solubility

  = √ (5.1 x 10^-9)

  = 7.1 x 10^-5 M  

Therefore;

Mass BaCO3 = 7.1 x 10^-5 M x 1 L x 197.34 g/mol

                      = 0.014 g

3 0
3 years ago
5. If a block of wood has a density of 0.6 g/cm3 and a mass of 120 g, what is its volume? (D= M/V)
AlexFokin [52]

Answer:

200 cm^3

Explanation:

V = M/D

V = 120g / (0.6g/cm^3)

V = 200 cm^3

4 0
3 years ago
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