Answer: C(s) + O2(g) --> CO2(g)12g (C) .... 50.8g (O2)................. initial amounts0g(C) .........18.8g(O2) ................. amounts when reaction completeThat means that C was the limiting reactant, and the amount of CO2 is based on the amount of carbon that burned. Covert 12 grams of carbon to moles. The moles of CO2 will be the same, since they are in a 1:1 mole ratio. Then convert the moles of CO2 to grams.12g C x (1 mol C / 12.0 g C) x (1 mol CO2 / 1 mol C) x (44.0g CO2 / 1 mol CO2) =44 g of CO2
Water molecules are made of hydrogen atoms and one oxygen atom.
Hope this helped!
The percent yield is 45 %.
CaCO₃ →CaO + CO₂
First, calculate the theoretical yield of CaO.
Theor. yield =
60 g CaCO
3
×
1 mol CaCO
3
100.0 g CaCO
3
×
1 mol CaO
1 mol CaCO
3
×
56.08 g CaO
1 mol CaO
=
33.6 g CaO
Now calculate the percent yield.
% yield =
actual yield
theoretical yield
×
100
%
=
15 g
33.6 g
×
100
%
=
45
Answer:
To stabilize themselves by sharing of electrons, mostly obey octate rule to complete their shells.
Explanation:
Understood... Each thing in this universe want to be stabilize, including you!
